A' = (1/2)*A = (8, 0)
B' = (1/2)*B = (12, 6)
C' = (1/2)*C = (6, 8)
The third choice is appropriate.
10/18 because 18-8=10 and the total amount is 18 so the fraction is 10/18
Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,
V(X)=α2σ2X¯1+β2\sigma2X¯2
Now we want to minimise this subject to α+β=1 or α−β−1=0.
We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise
f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).
We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;
∂f∂α=2ασ2X¯1+λ=0
∂f∂β=2βσ2X¯2+λ=0
∂f∂λ=α+β−1=0
Setting the first two partial derivatives equal we get
α=βσ2X¯2σ2X¯1
Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.
Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd
Answer:
4 bag's
Step-by-step explanation:
Given the bean bag made by beth is in the shape of cube with each side of the cube equal to 2 feet.
Now Also given that each bean bag holds 2 cubic feet of beans.
Let the number of bags of beans recquired are x
The total number of beans available are 2x cubic feet
Now the volume of the bean bag made by beth is
Volume =
Volume = 8 cubic feet
Now 8 = 2x
x = 4
Therefore the number of bag's of beans recquired are 4
They would meet 30 times after 10 minutes.
Since Nick and Sally run on the 100m straight track, and Nicks's speed is 3m / s, while Sally's speed is 2m / s, if they both start from two sides of the track, running towards each other continuously, to determine how many times they would meet each other after 10 minutes the following calculation should be performed:
- 30 x 20 + 2 x 20 = 60 + 40 = 100
- 10 minutes = 600 seconds
- 600/20 = X
- 30 = X
Therefore, they would meet 30 times after 10 minutes.
Learn more about maths in brainly.com/question/25849676
