Answer:
There are 42 quarters (and 6 dimes).
Step-by-step explanation:
The given ratio is 2:14. But this does not tell us how many dimes nor how many quarters we have. Instead, it's a ratio. Modify this by multiplying numerator and denominator by n and then find n:
Number of dimes 2n
----------------------------- = -----
Number of quarters 14n
Then the total number of coins is 2n + 14n =48, implying that:
16n = 48, or n = 3.
Then the number of dimes is 2(n) = 2(3) = 6, and that of quarters is 14(n) =
14(3) = 42.
There are 42 quarters (and 6 dimes). Notice how the total of 42 and 6 is 48.
Ok so you find squares
example
we know ataht √9=3 becuase 9=3*3 so √9=√(3 times 3)=√(3^2) =3
so we factor 230
230=2 times 5 times 23
we do not have any doubles so this is simplest form
Answer: q = 40
Step-by-step explanation:
Given the quadratic formula as
x = [-b +/-√(b^2 -4ac)]/2a
b = -14
a = 1
c = q
Difference d between the two roots.
d = [-b + √(b^2 -4ac)]/2a - [-b -√(b^2 -4ac)]/2a
d = 2√(b^2 -4ac)/2a
d = √(b^2 -4ac)/a
And d = 6
Substituting the values of a,b and c. We have;
6 = √[(-14^2) - (4×1×q)]
Square both sides
6^2 = 196 - 4q
4q = 196 - 36
q = 160/4
q = 40
The equation becomes
x^2 - 14x + 40 = 0
Answer:
x=5 twice
Step-by-step explanation:
x^2-10x+25=0
multiply the coefficient of x^2 and the last term
1X25=25
find two numbers you can multiply to get 25 and add to get -10
-5 + (-5)=-10 the middle term
replace -10x with -5x -5x and solve the equation
x^2-5x-5x+25=0
factorise by grouping
x(x-5)-5(x-5)=0
(x-5)(x-5)=0
Either x-5=0,x=5 or x-5=0,x=5
Therefore x=5 twice.
Well, We have to Know What The Distance is to the Finish Line. product of is multiplication.
