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kondaur [170]
2 years ago
13

The image is not drawn to scale. Which is the measure of ∠A?

Mathematics
1 answer:
dusya [7]2 years ago
7 0

Answer:

Step-by-step explanation:

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The change in water vapor in a cloud is modeled by a polynomial function, C(x). C(x) = x^3+ 5x^2+3x+30 Describe how to find the
kari74 [83]

Answer:

Suppose the equation that describes the change in water vapor in a cloud (y) with respect to temperature (x): C(x) = x³ - 4x² - 7x + 10

You find the x-intercepts of the cubic equation by finding the roots. Let y be zero:

x³ - 4x² - 7x + 10 = 0

Now, find possible factors of the constant term in the equation: 10. These could be 1, 2, 5, and 10. Suppose we choose 1. We substitute x=1. If the answer is zero, then x=1 is one of the roots.

(1)³ - 4(1)² - 7(1) + 10 = 0

Hence, x=1 or x-1 = 0 is one of the roots. We use this to manipulate the rest of the terms in the original equation, such that you can factor out (x-1). Substitute -x² - 3x² to -4x³ because they are just equal. Same is true for +3x - 10x for -7x:

x³ -x² - 3x²+3x - 10x + 10 = 0

Factor out like terms such that they have a common factor of (x-1) as much as possible.

x³ -x² = x²(x-1)

- 3x²+3x = -3x(x-1)

- 10x + 10 = -10(x-1)

The factored equation is:

x²(x-1)-3x(x-1)-10(x-1) = 0

Factor out (x-1):

(x-1)(x²-3x-10) = 0

Now, we have the quadratic equation left to be solved:x²-3x-10

Use the quadratic formula to find the roots:

x = [-b +/- √(b²-4ac)]/2a,

The a, b and c coefficients are based on the general form of the quadratic equation: ax² + bx + c. Hence, a=1, b=-3 and c=-10. Substituting the values:

x = [-(-3) +/- √((-3)²-4(1)(-10))]/2(1)

x = 5, -2

Therefore, the roots of the cubic equations are x = 1, x = 5 and x =- 2. These are the x-intercepts of the equation. At temperatures °C, 5°C and -2°C, there is no change in water vapor in a cloud. The graph is shown in the attached picture

Step-by-step explanation:

7 0
2 years ago
jada applies two transformations to a polygon in the coordinate plane One of the translations is a translation and the pother is
anygoal [31]

Answer:

What other information does Jada need to communicate about this sequence of transformations

Step-by-step explanation:

4 0
3 years ago
Two integers have a sum of -44 and a difference of 22. The greater of the two integers is
Leni [432]

Answer:

  -11

Step-by-step explanation:

The generic solution to ...

  • a + b = sum
  • a - b = difference

Can be found by adding the two equations:

  (a+b) + (a-b) = (sum) + (difference)

  2a = (sum + difference)

  a = (sum + difference)/2

___

Our particular solution is ...

  a = (-44 +22)/2 = -11

The greater of the two numbers is -11.

___

The other number is -33.

5 0
3 years ago
PLEASE HELP Word problem involving average rate of change
oee [108]

Answer:

(a): 26.1

(b): 27.9

Please see below for the steps.

Step-by-step explanation:

(a):

Use points (0,0) and (3, 78.3)

Use slope formula. The slope formula is also used to find average rate of change (just so you know).

y2-y1/x2-x1

78.3-0/3-0=78.3/3=26.1

Answer for (a) is 26.1

(b):

Use points (4, 147.6) and (9, 287.1)

Use slope formula.

y2-y1/x2-x1

287.1-147.6/9-4=139.5/5=27.9

The answer for (b) is 27.9

Hope this helps!

Please mark as brainliest if correct!

Have a great day!

5 0
1 year ago
Find the missing lengths:<br> LO=5 and OK=4, find OH and KH.
hodyreva [135]

Answer:

The length of KH is 6 units and OH is 6.3 units.

Step-by-step explanation:

Given the figure with lengths LO=5 and OK=4. we have to find the length of  OH and KH.

In ΔLOH

By Pythagoras theorem

LH^2=LO^2+OH^2\\\\LH^2=5^2+OH^2 → (1)

In ΔKOH,

KH^2=OH^2+OK^2\\\\KH^2=OH^2+4^2  → (2)

In ΔKHL,

KL^2=LH^2+KH^2

Using eq (1) and (2), we get

KL^2=5^2+OH^2+OH^2+4^2

9^2=25+2OH^2+16

⇒ 2OH^2=81-25-16=40

⇒ OH=\sqrt{20}=6.324\sim6.3units.

Put the above value in eq 2, we get

KH^2=20+4^2=36

⇒ KH=6 units.

8 0
3 years ago
Read 2 more answers
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