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Digiron [165]
3 years ago
15

0.7 x − 0.2 = 8.3 x + 7.2

Mathematics
2 answers:
stellarik [79]3 years ago
7 0

Answer: x=-0.97

Step-by-step explanation: see attachment

Svet_ta [14]3 years ago
3 0

Answer:

Wrong

Step-by-step explanation:

the variable have no value and there is a new number in the second expression.

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What is 1/30 as a decimal
Damm [24]

Answer:

0.0333333333

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.
faust18 [17]

Answer:

a. Tim has completed a greater amount of work.

b. Together they have completed \frac{142}{143} part of two projects.

Step-by-step explanation:

Let us assume that the project on which Jaime and Tim are working has x amount of space.

Now, given that Jaime has 5 over 11 space of a project completed while Tim has finished 7 over 13 space of the same project.

Therefore, Jaime has completed \frac{5x}{11} amount of space and Tim has finished \frac{7x}{13} amount of space.

a. Now, (7x) \times 11 > (5x) \times 13

⇒ \frac{7x}{13} > \frac{5x}{11}

Therefore, Tim has completed the greater amount of work. (Answer)

b. Together they have completed (\frac{7x}{13} + \frac{5x}{11}) = \frac{(7 \times 11 + 5 \times 13)}{13 \times 11} x = \frac{142}{143}x amount of space out of 2x amount of space. (Answer)

4 0
3 years ago
Solve this simultaneous equation x/2+ y/3=13/6 2x/7-y/4=5/14
Yuri [45]

9514 1404 393

Answer:

  (x, y) = (3, 2)

Step-by-step explanation:

These look like solution using elimination or substitution could be tedious, so we'll use the "cross multiplication" technique for solution. This requires each equation be in general form: ax+by+c = 0.

The first equation can be multiplied by 6 and 13 subtracted.

  x/2 +y/3 = 13/6

  3x +2y = 13

  3x +2y -13 = 0

The second equation can be multiplied by 28 and 10 subtracted.

  2x/7 -y/4 = 5/14

  8x -7y = 10

  8x -7y -10 = 0

Now, an array of coefficients can be constructed. The last column is the same as the first.

  \begin{array}{cccc}3&2&-13&3\\8&-7&-10&8\end{array}

Cross-multiplying adjacent columns, we can write the equation ...

  1/(3(-7)-8(2)) = x/(2(-10)-(-7)(-13)) = y/(-13(8)-(-10)(3))

  1/-37 = x/-111 = y/-74

Solving for x and y, we have ...

  x = -111/-37 = 3

  y = -74/-37 = 2

The solution is (x, y) = (3, 2).

4 0
3 years ago
A coin is flipped five times. Find the number of possible sets of heads and tails that have at most 3 heads
Mumz [18]

Answer:

Sets = 27

Step-by-step explanation:

Given

Coin = 1

Toss = 5

Required

Number of outcomes with at most 3 heads

First, we list out the sample space of a toss of coin 5 times

(HHHHH), (HHHHT), (HHHTT), (HHTTT), (HTTTT), (TTTTT), (TTTTH), (TTTHH), (TTHHH), (THHHH), (HTHTH), (THTHT), (HHTHH), (TTHTT), (HTTHT), (THHTH), (THHHT), (HTTTH), (THHTT), (HTTHH), (HHTTH), (TTHHT), (TTHTH), (HHTHT), (HTHTT), (THTHH), (THTTH), (HTHHT), (HTHTT), (THTHH), (HHHTH), (TTTHT)

Next, we list out all outcomes with at most 3 heads

, , (HHHTT), (HHTTT), (HTTTT), (TTTTT), (TTTTH), (TTTHH), (TTHHH), , (HTHTH), (THTHT), , (TTHTT), (HTTHT), (THHTH), (THHHT), (HTTTH), (THHTT), (HTTHH), (HHTTH), (TTHHT), (TTHTH), (HHTHT), (HTHTT), (THTHH), (THTTH), (HTHHT), (HTHTT), (THTHH), (TTTHT)

So, the number of set is:

Sets = 27

4 0
4 years ago
Car A went 60 km in 5 6 hour while a car B went 54 km in 2 3 hour. Which car was faster? How many times faster?
Alexxx [7]

Answer:car B is faster

Step-by-step explanation:

Car A:

Speed=distance ➗ time

Speed=60 ➗ 5/6

Speed=60 x 6/5

Speed=(60x6)/5

Speed=360/5

Speed of car A=72 km/hr

Car B:

Speed=distance ➗ time

Speed=54 ➗ 2/3

Speed=54 ➗ 2/3

Speed=54 x 3/2

Speed=(54x3)/2

Speed=162/2

Speed of car B=81 km/hr

Therefore car B is faster

4 0
4 years ago
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