First, let's find what m is, the slope of the line...
m= y2-y1/x2-x1
m=7-4/3-2 You end up with 3/1 or 3 as your slope.
so far you have... y=3x+b
<span>Take (2,4). y=mx+b or 4=3*2+b, solving for b: b=4-(3)(2). b=-2.</span>
So your final equation is...
<span>y = 3x-2</span>
29
Note that consecutive numbers have a difference of 1 between them.
let n be the smallest integer then the three integers can be expressed as
n, n + 1 , n + 2
the sum is then
n + n + 1 + n + 2 = 90
3n + 3 = 90
subtract 3 from both sides of the equation
3n = 90 - 3 = 87
divide both sides by 3
n =
= 29
the three integers are 29, 30, 31 → the smallest is 29
4 because when u solve it that’s what you get