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3 years ago

Give me an example of theory

Physics

2 answers:

horrorfan [7]3 years ago

3 0

Answer:

theory is an idea to explain something,

Explanation:

Einstein's ideas about relativity are an example of the theory of relativity.

lesya692 [45]3 years ago

3 0

Answer: If skin cancer is related to ultraviolet light, then people with a high exposure to uv light will have a higher frequency of skin cancer.

Explanation:

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¿Tres ejemplos de rozamiento cinético?

Verizon [17]

Answer:

Un automóvil en movimiento en una carretera.

Una piedra rodando por una colina.

Un hierro que se empuja a través del materia

4 0

3 years ago

A merry-go-round accelerating uniformly from rest achieves itsoperating speed of 2.5rpm in five revolution.

g100num [7]

Answer:

(A) The magnitude of its angular acceleration 1.09 x 10⁻³ rad/s²

(B) Time of motion 240.2 s

Explanation:

Given;

final angular speed, ωf = 2.5 RPM

angular distance, θ = 5 rev = 5 x 2π = 10π rad

initial angular speed, ωi = 0

final angular speed in rad/s;

$\omega_f = \frac{2.5 \ rev}{min} \times \ \frac{2\pi}{1 \ rev} \times \ \frac{1 \min}{60 s} = 0.2618 \ rad/s \\$

(A) the magnitude of its angular acceleration(rad/s^2);

$\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\(0.2618)^2 = 0 + (2\times 10\pi)\alpha\\\\0.0685 = 20\pi \alpha\\\\\alpha = \frac{0.0685}{20\pi} \\\\\alpha = 1.09\times 10^{-3} \ rad/s^2$

(B) Time of motion;

$\omega_f = \omega_i + \alpha t\\\\0.2618 = 0 + 1.09\times 10^{-3} t\\\\t = \frac{0.2618}{1.09\times 10^{-3}} \\\\t = 240.2 \ s$

7 0

3 years ago

Chris and Sue are wearing harnesses and are hanging from the ceiling by means of ropes attached to them. They are face to face a

Setler [38]

Answer:

h = 0.288m

Explanation:

Assume

$v_1$ = Speed of Sue

$v_2$ = Speed of Chris immediately after the push

Sue's KE = $\frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2$

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65

= 331.24

$26v_{1}\ ^2$ = 331.24

So, $v_1 = 3.569$

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

$m_1v_1 = m_2v_2$