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Elden [556K]
4 years ago
11

An electron is placed in a magnetic field that is directed along a z axis. The energy difference between parallel and antiparall

el alignments of the z component of the electron's spin magnetic moment with is 7.50 × 10-25 J. What is the magnitude of ?
Physics
1 answer:
Luda [366]4 years ago
8 0

Answer:

B = 0.0404 т

Explanation:

Given

ΔE = 7.50 x 10⁻²⁵ J

μb = 927.4 x 10⁻²⁶ J/т

ΔE = 2 * μb * B

B = ΔE / 2 μb

B = 7.50 x 10⁻²⁵ /  2 * 927.4 x 10⁻²⁶

B = 7.50 / 1854.8 x 10⁻²⁵⁻⁽⁻²⁶⁾

B = 0.00404 x 10¹

B = 0.0404 т

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You toss a ball straight up with an initial speed of 30m/s. How high does it go, and how long is it in the air (neglecting air r
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Explanation:

Given that,

A ball is tossed straight up with an initial speed of 30 m/s

We need to find the height it will go and the time it takes in the air.

At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :

v = u +at

Here, a = -g

v = u -gt

i.e. u = gt

t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s

So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds

Let d is the maximum distance covered by it.

d=ut-\dfrac{1}{2}gt^2

Putting all values

d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m

Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.

8 0
3 years ago
A marathon runner completes a 42.238 km course in 2 h, 31 min, and 46 s . There is an uncertainty of 29 m in the distance run an
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Answer:

The percentage uncertainty in the average speed is 0.10% (2 sig. fig.)

Explanation:

Consider the formula for average speed \bar{v}.

\displaystyle \bar{v} = \frac{s}{t},

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  • t is the time taken.

The percentage uncertainty of a fraction is the sum of percentage uncertainties in

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What are the percentage uncertainties in s and t in this question?

The unit of the absolute uncertainty in s is meters. Thus, convert the unit of s to meters:

s = \rm 42.238\;km = 42.238\times 10^{3}\;m.

\begin{aligned}\displaystyle \text{Percentage Uncertainty in }s &= \frac{\text{Absolute Uncertainty in } s}{\text{Measured Value of }s}\times 100\% \\ &=\rm\frac{29\; m}{42.238\times 10^{3}\;m}\times 100\%\\ &= 0.0687\%\end{aligned}.

The unit of the absolute uncertainty in t is seconds. Convert the unit of t to seconds:

t = \rm 2\times 3600 + 31\times 60 + 46 = 9106\;s

Similarly,

\begin{aligned}\displaystyle \rm \text{Percentage Uncertainty in }t &= \frac{\text{Absolute Uncertainty in }t}{\text{Measured Value of }t}\times 100\% \\ &=\rm\frac{46\; s}{9106\;s}\times 100\%\\ &= 0.0329\%\end{aligned}.

The average speed \bar{v} here is a fraction of s and t. Both s and t come with uncertainty. The percentage uncertainty in \bar{v} will be the sum of percentage uncertainties in s and t. That is:

\text{Percentage Uncertainty in }\bar{v}\\=(\text{Percentage Uncertainty in } s) + (\text{Percentage Uncertainty in } t)\\ = 0.0687\% + 0.0329\%\\ = 0.010\%.

Generally, keep

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The percentage uncertainty in \bar{v} here is less than 2%. Thus, keep two significant figures. However, keep more significant figures than that in calculations to make sure that the final result is accurate.

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Each horizontal row is called a period.

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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