Question

Radio astronomers detect electromagnetic radiation at 44.0 MHz from an interstellar gas cloud. They suspect this radiation is emitted by electrons spiraling in a magnetic field.What is the magnetic field strength inside the gas cloud?

Answer 1

Answer:

The magnetic field strength is  $B = 1.57*10^{-3} \ T$

Explanation:

The objective of the solution is to obtain the magnetic field strength inside the gas cloud and in order to do so we would be employing the mathematical expression of magnetic field strength which is represented as

                    $B = \frac{2 \pi f m}{q}$

Where B is the magnetic field strength

           f is the frequency

           m is the mass

           q is the  charge

From the question

       $f = 44.0MHz = 44.0*10^{6}Hz$

Generally the mass of an electron which is the is particle

     $m = 9.11*10^{-31}kg$

And the charge q is generally

        $q= 1.6*10^{-19} C$

Note that this electromagnetic radiation with frequency 44.0MHz is a moving electron mass

   substituting these values into the equation for the magnetic field strength

                $B = \frac{2 \pi (44*10^{6})(9.11*10^{-31})}{1.6*10^{-19}} = 1.57*10^{-3} T$