Answer:
200 m/s
Explanation:
v = distance / time = 50km/250s = 50000m/250s = 200 m/s
Answer:
2.61 atm
Ley de Boyle
Explanation:
= Presión inicial = 0.96 atm
= Presión final
= Volumen inicial = 95 mL
= Volumen final = 35 mL
En este problema usaremos la ley de Boyle.

La presión ejercida sobre el émbolo para reducir su volumen es de 2.61 atm.
Answer:
a)q= 2800 W/m²
b)To=59.4°C
Explanation:
Given that
L = 10 mm
K= 20 W/m·K
T=30°C
h= 100 W/m²K
Ti=58°C
a)
Heat flux q
q= h ΔT
q= 100 x (58 - 30 )
q= 2800 W/m²
b)
As we know that heat transfer by Fourier law given as
Q= K A ΔT/L
Lets take outer temperature is To
So by Fourier law
To= Ti + qL/K
Now by putting the values
To= Ti + qL/K

To=59.4°C
Answer:
Answer is = 12.3 x 10^6 N
Explanation:
We need to calculate force on the charge which is in Newtons:
Formula is = K q1q2/r^2
k is constant depeneds on the permitivity of the medium and its value is 9x10^9 Nm^2/C^2
q1 and q2 are charges and r is the distance between these two charges so just by putting values we get F= 9x10^9 x 1.1x10^-6/(8x10^-2)^2 (we get the above answer in newton)