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4 years ago

3.

Physics

1 answer:

alexandr402 [8]4 years ago

4 0

Answer:

1.92 m/s

Explanation:

Velocity is defined as the distance moved per unit time with consideration of the direction. The direction aspect differentiates speed from velocity since for speed, we don't need to consider the direction.

$v=\frac {d}{t}$

Distance moved for circular path is equal to its circumference and the circumference is given by $2\pi r$ where r is the radius and substituting $2\pi r$ for d then

$v=\frac {2\pi r}{t}$

Substituting 5.5 m for r and 18 s for t then

$v=\frac {2\pi \times 5.5}{18}=1.919862177 m/s\approx 1.92 m/s$

To the nearest hundredth, the velocity is 1.92 m/s

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A client has developed dystrophic calcification as a result of macroscopic deposition of calcium salts. The tissue that would be

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Answer:

Tissues that are damaged or injured.

Explanation:

Dystrophic calcification involves the deposition of calcium in soft tissues despite no disturbance in the calcium metabolism, and this is often seen at damaged tissues.

Examples of areas in the body where dystrophic calcification can occur include atherosclerotic plaques and damaged heart valves.

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3 years ago

What is the net torque on the square plate, with sides 0.2 m, from each of the three forces? F1=18 N, F2=26 N, and F3=14 N. Use

marshall27 [118]

Answer:

The net torque on the square plate is 2.72 N-m.

Explanation:

Given that,

Side = 0.2 m

Force $F_{1}=18\ N$

Force $F_{2}=26\ N$

Force $F_{3}=14\ N$

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Using formula of torque

$\tau_{1}=-F_{1}d_{1}$

$\tau_{1}=-F_{1}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{1}=-18\times\dfrac{0.2}{2}$

$\tau_{1}=-1.8\ N-m$

We need to calculate the torque due to force F₂

Using formula of torque

$\tau_{2}=F_{2}d_{2}$

$\tau_{2}=F_{2}\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{2}=26\times\dfrac{0.2}{2}$

$\tau_{2}=2.6\ N-m$

We need to calculate the torque due to force F₃

Using formula of torque

$\tau_{3}=F_{3}d_{3}$

$\tau_{3}=(F_{3}\sin45+F_{3}\cos45)\times\dfrac{a}{2}$

Put the value into the formula

$\tau_{3}=0.1(14\sin45+14\cos45)$

$\tau_{3}=1.92\ N-m$

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$\tau=\tau_{1}+\tau_{2}+\tau_{3}$

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4 years ago

A 50-V de voltage source was connected in series with a resistor and capacitor. Calculate the current in A to two significant fi

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Answer:

Current through circuit will be $0.2706\times 10^6A$

Explanation:

We have given source voltage v = 50 volt

Resistance $R=25Mohm=25\times 10^6ohm$

Capacitance $C=0.1\mu F=0.1\times 10^{-6}F$

Time t = 5 sec

Time constant of RC circuit is given by $\tau =RC=25\times 10^6\times 0.1\times 10^{-6}=2.5sec$

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Answer:

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3 years ago

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Answer:

Explanation:

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3 years ago