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Taya2010 [7]
3 years ago
7

Do

Physics
1 answer:
kondaur [170]3 years ago
3 0

Explanation

hii there

The radius of gyration depends upon shape and size of the body, position and configuration of the axis of rotation, and also on the distribution of the mass of the body wrt the axis of rotation. Radius of gyration is defined as the distance between the center of gravity and the axis about which body is rotating .

hope this answer correct

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Explain the importance of units by
IrinaVladis [17]

Answer:

Look below

Explanation:

Units are very important. Let's say we were building an apartment. We used meters for every measurement except for 1 support where we used centimeters. This could lead to the collapse of the whole structure as the measurements were wrong. 100 meters and 100 centimeters are very different.

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3 years ago
Which one is Transverse Wave?
nekit [7.7K]

Answer:a

Explanation:

7 0
3 years ago
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PLEASE HELP ME, 100 POINTS!! WRITE A 2 PAGE STORY IF YOU WERE A TINY WATER MOLECULE AND YOU WERE TRAVELING THROUGH THE WATER CYC
maksim [4K]

Answer:

Explanation:

pointers for comedy.

1. dont just add jokes in at random places. you have to make the whole thing funny. not just random spurts of funny

2. use sentences like, "evaporation can be really fun. first you are holding hands with other molecules forming a puddle then you shoot up into space. When you reach the top you get stuck to sand and you fall back to the earth."

3. if you simplify the processes so a child could understand them then it will be easier to make them funny.

4. once you get started it will be easier to keep it funny.

Hope this helps and you can understand it (it makes sense to me but it might not make sense to you)

3 0
4 years ago
Steam enters the condenser of a steam power plant at 20kPa and a quality of 95% with a mass flow rate of 20,000kg/h. It is to be
avanturin [10]

Answer:

The mass rate of the cooling water required is: 1'072988.5\frac{kg}{h}

Explanation:

First, write the energy balance for the condensator: The energy that enters to the equipment is the same that goes out from it; consider that there is no heat transfer to the surroundings and kinetic and potential energy changes are despreciable.

{m_{w}}*{h_{w}}^{in}+m_s{h_{s}}^{in}=m_w{h_{w}}^{out}+m_s{h_{s}}^{out}

Where w refers to the cooling water and s to the steam flow. Reorganizing,

m_w({h_{w}}^{out}-{h_{w}}^{in})=m_s({h_{s}}^{in}-{h_{s}}^{out})\\m_w=\frac{m_s({h_{s}}^{in}-{h_{s}}^{out})}{({h_{w}}^{out}-{h_{w}}^{in})}

Write the difference of enthalpy for water as Cp (Tout-Tin):

m_w=\frac{m_s({h_{s}}^{in}-{h_{s}}^{out})}{C_{pw}({T_{w}}^{out}-{T_{w}}^{in})}

This equation will let us to calculate the mass rate required. Now, let's get the enthalpy and Cp data. The enthalpies can be read from the steam tables (I attach the tables I used). According to that, {h_{s}}^{out}=251.40\frac{kJ}{kg} and {h_{s}}^{in} can be calculated as:

{h_{s}}^{in}={h_{f}}+x{h_{fg}}=251.40+0.95*2358.3=2491.8\frac{kJ}{kg}.

The Cp of water at 25ºC (which is the expected average temperature for water) is: 4.176 \frac{kJ}{kgK}. If the average temperature is actually different, it won't mean a considerable mistake. Also we know that {T_{w}}^{out}-{T_{w}}^{in}\leq 10, so let's work with the limit case, which is {T_{w}}^{out}-{T_{w}}^{in}=10 to calculate the minimum cooling water mass rate required (A higher one will give a lower temperature difference as a result). Finally, replace data:

m_w=\frac{20000\frac{kg}{h}(2491.8-251.40)\frac{kJ}{kg} }{4.176\frac{kJ}{kgK} (10C)}=1'072988.5\frac{kg}{h}

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5 0
3 years ago
A car starts from rest and accelerates along a straight line path in one minute. It finally attains a velocity of 40 meters/seco
igomit [66]
It is very important to note down all the details that are given in the question. Based on these details the answer can be derived.
Initial velocity of the car (V1) = 0 meters/second
Final velocity of the car (V2) = 40 meters/second
Initial time (T1) = 0 Second
Final time (T2) = 60 seconds (In this case we have converted 1 minute into 60 seconds for the ease of calculation.
Then
Average acceleration = (V2 - V1)/ (T2 - T1) m/s^2
                                   = (40 - 0)/(60 - 0) m/s^2
                                   = 40/60 m/s^2
                                   = 2/3 m/s^2
                                   = 0.67 m/s^2
So the average acceleration of the car is 0.67 meters/second square.
7 0
4 years ago
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