1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STatiana [176]
3 years ago
11

The mechanical energy of a bicycle at the top of a hill is 6,000 J. The bicycle stops at the bottom of the hill by applying the

brakes. If the potential energy of the bicycle is 2,000 J at the bottom of the hill, how much thermal energy was produced?
Physics
1 answer:
Semmy [17]3 years ago
7 0

Answer:

Thermal energy produce =4,000 J.

Explanation:

Given that

Mechanical  energy at the top of hill = 6,000 J

Mechanical  energy at the bottom of hill = 2,000 J

We know that energy is conserve

Energy at top of hill = energy at bottom of hill + Thermal energy produce

So now by putting the values

Energy at top of hill = energy at bottom of hill + Thermal energy produce

6,000 = 2,000+ Thermal energy produce

Thermal energy produce =6,000-2,000 J

Thermal energy produce =4,000 J.

As we know that thermal energy produce due to friction when one mechanical component slides on the other mechanical component then always heat is generated and this heat is known as thermal energy.

You might be interested in
7. A mother pushes her 9.5 kg baby in her 5kg baby carriage over the grass with a force of 110N @ an angle
jasenka [17]

Weight of the carriage =(m+M)g =142.1\ N

Normal force =Fsin(\theta) + W = 197.1\ N

Frictional force =\mu N=27.59\ N

Acceleration =4.66\ m\ s^{-2}

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

  • So Weight(W) =(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with F_x, force of 110\ N acting vertically downward.Both are downward and Normal is upward so Normal force =Summation\ of\ both\ forces

  • Normal force (N) = Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N
  • Frictional force (f) =\mu N=0.14\times 197.1 =27.59\ N

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that F_y=Horizontal and F_x=Vertical component of forces.

So Fnet = Fy(Horizontal) - f(friction) = m\times a

  • Acceleration (a) =\frac{Fcos(\theta)-\mu N}{mass(m)} =\frac{(95.26-27.59)}{14.5}= 4.66\ m\ s{^2 }

So we have the weight of the carriage, normal force,frictional force and acceleration.

3 0
3 years ago
In which of the following is positive work done by a person on a suitcase
MrRa [10]

pendajo sMh so stupid

4 0
3 years ago
Can someone help with thsi? i will give brainliest
kogti [31]

Answer:

40 meters. look for the dot above the 20 on the x-axis and follow it over to the left.

Explanation:

4 0
3 years ago
A student who weighs 750 newton’s runs up the steps (which have a height of 8 meters) in 13.5 seconds. How much work did the stu
nikklg [1K]

Answer:

B

Explanation:

6 0
2 years ago
A positively charged object is brought near but not in contact with the top of an uncharged gold leaf electroscope. The experime
Olin [163]

Answer:

The leaves of the electroscope move further apart.

Explanation:

This is what happens; when the positive object is brought near the top, negative charges migrating from the gold leaves to the top. This is because the negative charges in the gold are attracted by the positive charge. Thus, it leaves behind a net positive charge on the leaves, though the scope remains neutral overall. To that effect, the leaves repel each other and move apart. If a finger touches the top of the electroscope at the moment when the positive object remains near the top, it basically grounds the electroscope and thus the net positive charge in the leaves flows to the ground through the finger. However, the positive object continues to "hold" negative charges in place at the top. Ar this moment the gold leaves have lost their net positive charge, so they no longer repel, and they move closer together. If the positive object is moved away, the negative charges at the top are no longer attracted to the top, and they redistribute themselves throughout the electroscope, moving into the leaves and charging them negatively.

Thus, the leaves move apart from each other again and we now have a negatively charged electroscope. If a negatively charged object is now brought close to the top, but without touching, the negative charges already in the electroscope will be repelled down toward the leaves, thereby making them more negative, causing them to repel more, and hence move even further apart.

So, the leaves move further apart.

7 0
3 years ago
Other questions:
  • Please help on this one
    15·1 answer
  • A magnet can attract or repel another magnet from a distance true or false?
    15·2 answers
  • A 5 kg block is being pulled to the right by a rope tied to it. the block is accelerating at 2 m/s2 to the right. how much force
    8·2 answers
  • Gravitational force between two objects increases as mass increases and distance
    12·1 answer
  • The first part of the brain to be stimulated and affected by alcohol is the
    9·1 answer
  • There is a circuit with 4 amps and 10 ohm. what would the voltage be?
    6·1 answer
  • A locomotive is accelerating at 3.08 m/s2. It passes through a 20.8-m-wide crossing in a time of 2.93 s. After the locomotive le
    15·1 answer
  • I really need help with the graphs
    6·1 answer
  • PLS HELP BEING TIMED!!!
    9·2 answers
  • Please help me I will give a brainless
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!