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VARVARA [1.3K]
4 years ago
11

What is the answer to this equation?

Mathematics
1 answer:
Bezzdna [24]4 years ago
6 0
19c is the correct answer
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What should be done so that the expression 4+4 to the power of 2 - 5×2 will have a value of 10? ​
Olin [163]

Answer: 8 x 8 = 64 - 10 = 64  so you need add the another times operation 64 - 54 x 1 = 10

3 0
3 years ago
[khan academy]
deff fn [24]

Answer: point 1 is (-4,-6) point 2 is (-4,8)

Step-by-step explanation:

point D is located at (-4,1) with the x-coordinate being -4 and the y-coordinate being 1 so to get the points 7 units away with the same x-coordinate you:

1. subtract 7 from the y-coordinate in the original point (-4,1) and get (-4,-6) your first point

2. add 7 to the y-coordinate in the original point (-4,1) and get (-4,8) your second point

3 0
3 years ago
I cannot find the answer to my question
slamgirl [31]

Answer:

14M

Step-by-step explanation:

7*2*M

14*M

14M

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

        ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                       PEACE!

4 0
3 years ago
If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5%
vladimir1956 [14]

Complete Question

If $12000 is invested in an account in which the interest earned is continuously compounded at a rate of 2.5% for 3 years

Answer:

$ 12,934.61

Step-by-step explanation:

The formula for Compound Interest Compounded continuously is given as:

A = Pe^rt

A = Amount after t years

r = Interest rate = 2.5%

t = Time after t years = 3

P = Principal = Initial amount invested = $12,000

First, convert R percent to r a decimal

r = R/100

r = 2.5%/100

r = 0.025 per year,

Then, solve our equation for A

A = Pe^rt

A = 12,000 × e^(0.025 × 3)

A = $ 12,934.61

The total amount from compound interest on an original principal of $12,000.00 at a rate of 2.5% per year compounded continuously over 3 years is $ 12,934.61.

7 0
3 years ago
Andrew
PilotLPTM [1.2K]
Let's say Bailey takes "b" days to paint it.

and Andrew takes "a" days to paint the same house.

now, Andrew is 6 times faster than Bailey, therefore, if Andrew takes "a" days to do it, Bailey takes then "6a" days, or b = 6a.

now, the year they worked together, they finished it in 7 days.

so, after 1 day then, they have only done 1/7 of the whole work.

and Andrew for one day, has done 1/a of the house, whilst Bailey has done 1/b of the house or 1/(6a).

\bf \stackrel{\textit{Andrew's rate}}{\cfrac{1}{a}}+\stackrel{\textit{Bailey's rate}}{\cfrac{1}{b}}=\stackrel{\textit{1 day of work}}{\cfrac{1}{7}}
\\\\\\
\cfrac{1}{a}+\cfrac{1}{6a}=\cfrac{1}{7}\impliedby 
\begin{array}{llll}
\textit{let's multiply all by }\stackrel{LCD}{42a}\textit{ to toss the}\\
denominators
\end{array}

\bf 42a\left( \cfrac{1}{a}+\cfrac{1}{6a} \right)=42a\left( \cfrac{1}{7} \right)\implies 42+7=6a\implies \cfrac{49}{6}=a
\\\\\\
\stackrel{days}{8\frac{1}{6}}=a
\\\\\\
\textit{how many days will it take Bailey then?}\quad b=6a
\\\\\\
b=6\cdot \cfrac{49}{6}\implies b=\stackrel{days}{49}
6 0
4 years ago
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