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Jet001 [13]
3 years ago
15

Which of the following best characterizes the field of chemistry, A) Scientific study of the laws of nature and the origin of al

l the things around us B) Scientific study of matter and how materials interact with each other at the atomic level C) Scientific study of how celestial objects move?
Physics
2 answers:
sesenic [268]3 years ago
8 0
B) <span>Scientific study of matter and how materials interact with each other at the atomic level
b/c chem has to do with atoms
</span>
Mkey [24]3 years ago
7 0

Answer:

B) Scientific study of matter and how materials interact with each other at the atomic level

Explanation:

Natural science deals with the study of all the aspects of our universe. Natural sciences consist of Biology, Chemistry and Physics.

Chemistry is the study of interactions of matter at a sub atomic or atomic scale or molecular scale.

Physics is the study of the fundamental laws that govern our universe.

Astronomy deals with the study of celestial objects.

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Which equation is used to calculate the magnetic force on a charge moving in a magnetic field?
JulijaS [17]

The force is perpendicular to the plane formed by v and B. Since the force is zero if v is parallel to B, charged particles often follow magnetic field lines rather than cross them.

B) F = |q|vBsin

7 0
3 years ago
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Why do we call the microscope a compound light microscope
Ede4ka [16]

Explanation:

Types of light microscope

1. Compound , and 2. Stereo Microscope

Compound microscope has two lens system also called compound lens system. The objective lens and the eyepiece lens. The magnification provided by the objective lens is compounded by the eyepiece lens, the a higher magnification is observed.

6 0
3 years ago
Two electrons are initially at rest separated by a distance of 2nm. At time t=0, they start to move apart due to Coulombic repul
Gnom [1K]

Answer:

t=2.5\times 10^{-14}\ s

Explanation:

We know that charge on electron

q=1.6\times 10^{-19}\ C

r= 2 nm

We know that force between two charge given

F=K\dfrac{Q_1Q_2}{r^2}

Now by putting the value

F=9\times10^9\dfrac{1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(2\times 10^{-9})^2}

F=5.67\times 10^{-11}\ N

We know that mass of electron

The mass of electron

m=9.1\times 10^{-31}\ kg

F= m a

a= Acceleration of electron

a= F/m

a=\dfrac{5.67\times 10^{-11}}{9.1\times 10^{-31}}\ m/s^2

a=6.2\times 10^{19} m/s^2

S=ut+\dfrac{1}{2}at^2

initial velocity given that zero ,u=0

20\times 10^{-9}=\dfrac{1}{2}\times 6.2\times 10^{19} t^2

t=\sqrt {\dfrac{40\times 10^{-9}}{6.2\times 10^{19}}}

t=2.5\times 10^{-14}\ s

3 0
3 years ago
Un móvil se encuentra en la posición inicial x0 = 22 m, y se mueve con velocidad 5 m/s. Calcula la posición en la que se encuent
Brilliant_brown [7]

Answer:

La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.

Explanation:

El movimiento rectilíneo uniforme (MRU) es el movimiento que describe un cuerpo o partícula a través de una línea recta a velocidad constante.

La distancia recorrida,  x , por un móvil que tiene un MRU con un velocidad  v  durante el intervalo de tiempo  t  es:

x= x0 + v*t

donde x0 es la posición inicial.

En este caso:

  • x0= 22 m
  • v= 5 m/s
  • t= 30 s

Reemplazando:

x= 22 m + 5 m/s* 30 s

Resolviendo:

x= 22 m + 150 m

x= 172 m

<u><em>La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.</em></u>

8 0
3 years ago
There is no law of conservation​
ruslelena [56]

Answer:

yes

Explanation:

I think so because it not mention in the law

3 0
3 years ago
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