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Ksivusya [100]
3 years ago
15

_______ are pictures of relationships.

Physics
2 answers:
Levart [38]3 years ago
6 0
Graphs. Can I get brainlessly??
S_A_V [24]3 years ago
5 0

Answer:

Graphs

Explanation:

You might be interested in
A typical nuclear fission power plant produces about 1.00 GW of electrical power. Assume the plant has an overall efficiency of
mamaluj [8]

Answer:

mass consumed by 235U each day = 2 kg

Explanation:

electrical power produced = 1 GW = 1 × 10⁹ × (6.24151 × 10¹⁸ ) eV

                                            = 6.24151× 10²¹ MeV/s

thermal energy =  0.420 * 250 = 105 MeV

\dfrac{1 GW}{150 MeV}= \dfrac{6.24151\times 10^{21}}{105}

                                      = 5.94 × 10¹⁹ fission/second

                                       =5.94 × 10¹⁹× 24 × 60 ×60)

                                      =  5.13 × 10²⁴ fission/day

mu = 235.04393 ×  1.660× 10 ⁻²⁷ = 390.1729× 10⁻²⁷ Kg

M = mu ×5.13 × 10²⁴

   = 390.1729× 10⁻²⁷ ×5.13 × 10²⁴

M   =  2 kg(approx.)

mass consumed by 235U each day = 2 kg

3 0
3 years ago
3. How do electric and magnetic forces act on different object?
zloy xaker [14]
The answer is C I believe
8 0
4 years ago
Laura adds 50mL of boiling water to 100mL of ice water. If the 150 mL of water is then put into a freezer, at what temperature w
Dennis_Churaev [7]
Water that is pure, will always freeze at 0 degrees.
8 0
3 years ago
Which statement best describes what happens when a sound source is moving? (1 point)
GREYUIT [131]

Answer:

As the sound approaches the observer, the pitch increases; as it passes the observer, the pitch decreases.

Explanation:

The crests come closer when it approaching, and go farther when the source passes the observer.

5 0
3 years ago
With what minimum speed must you toss a 200 g ball straight up to just touch the 12-m-high roof of the gymnasium if you release
masha68 [24]

Answer:

v = 14.41 m/s

Explanation:

It is given that,

mass of the ball, m = 200 g = 0.2 kg

Height of the roof, h = 12 m

The ball is tossed 1.4 m above the ground, h' = 1.4 m

Let v is the minimum speed with which the ball is tossed. Using the conservation of energy to find it as :

E_p=E_k

mg(h-h')=\dfrac{1}{2}mv^2

g(h-h')=\dfrac{1}{2}v^2

v=\sqrt{2g(h-h')}

v=\sqrt{2\times 9.8(12-1.4)}

v = 14.41 m/s

So, the minimum speed with which the ball is thrown straight up is 14.41 m/s. Hence, this is the required solution.

4 0
3 years ago
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