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3 years ago

Moving force of air flows through areas of high pressure to areas of low pressure

Physics

2 answers:

vazorg [7]3 years ago

7 0

The answer is true i hope this helps

Anvisha [2.4K]3 years ago

7 0

It's true your welcome

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A solenoid field is:

Bumek [7]

increased with an increased current flow

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3 years ago

A car moving with a speed of 35 m/s sees a child standing in the

zlopas [31]

Answer:

2100 N

Explanation:

$v = u + at \\ 0 = 35 + a(5) \\ a = - 7m {s}^{ - 2} \\ \\ net \: force \: = ma \\ = (300)(7) \\ = 2100 \: newtons$

6 0

3 years ago

A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.6 m/

jenyasd209 [6]

Answer:

$\Delta t =1.31\ s$

Explanation:

given,

coefficient of kinetic friction, μ = 0.25

Speed of sled at point A = 8.6 m/s

Speed of sled at point B = 5.4 m/s

time taken to travel from point A to B.

we know,

J = F Δ t

J is the impulse

where F is the frictional force.

t is the time.

we also know that impulse is equal to change in momentum.

$J = m(v_f - v_i)$

frictional force

F = μ N

where as N is the normal force

now,

$F\Delta t = m(v_f -v_i)$

$\mu m g \times \Delta t = m(v_f-v_i)$

$\mu g \times \Delta t = v_f-v_i$

$\Delta t =\dfrac{v_f-v_i}{\mu g}$

$\Delta t =\dfrac{8.6-5.4}{0.25\times 9.8}$

$\Delta t =1.31\ s$

time taken to move from A to B is equal to 1.31 s

3 0

3 years ago

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The ability of a singer to shatter glass is due to: <br> bending of a wave around an obstacle

Rzqust [24]

The ability of singers to shatter glass is due to the control of frequency in their voices. The sound waves will vibrate the air particles that surround the glass at its resonant frequency. The glass will break if a singer sings too loudly.

8 0

3 years ago

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radio signals emitted from and received by an airplane have her fruit frequency of 3.00 * 10 to the 12th Hertz and travel at the

Elanso [62]

here we know that the speed of the signal is same as the speed of light

so here we will have

$v = 3 \times 10^8 m/s$

the altitude of the airplane is given as

$h = 1 \times 10^4 m$

now we know that time taken by the signal to reach the control tower is given as

$t = \frac{d}{v}$

now it is given as

$t = \frac{1 \times 10^4 }{3 \times 10^8}$

$t = 3.33 \times 10^{-5} s$

so above is the time taken by the signal to reach the control tower

3 0

3 years ago