Complete Question
A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.
Answer:
The phase at the second point is 
Explanation:
From the question we are told that
The wavelength of the spherical wave is 
The first radius is 
The phase at that instant is 
The second radius is 
Generally the phase difference is mathematically represented as
this can also be expressed as
So we have that
substituting values
Large surface area, as more particles are able to bump into one another and transfer heat.
Doppler Shift lets you see a star A. Move back and forth
<h3>What is Doppler Shift?</h3>
This refers to the frequency change of a wave in relation to an observer as it moves back and forth.
Hence, we can see that the thing which astronomers can learn from the Radial Velocity Method is D. Period of orbit and minimum mass of a planet as it measures the wavelengths of absorption lines in its spectrum.
Read more about doppler shift here:
brainly.com/question/4052291
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Answer:
a= 17.877 m/s² : Magnitude of the acceleration of the flea
β = 88.21° : Direction of the acceleration of the flea
Explanation:
Conceptual analysis
We apply Newton's second law:
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Problem development
Look at the flea free body diagram in the attached graphic
The acceleration is presented in the direction of the resultant force (R) applied over the flea .
R= 10.905*10⁻⁶ N
We apply the formula (1) to calculate the magnitude of the acceleration of the flea
∑F = m*a m = 6.1 * 10⁻⁷ kg
R = m*a
a= R/m
a= (10.905*10⁻⁶) / (6.1 * 10⁻⁷ )
a= 17.877 m/s²
β: Direction and magnitude of the acceleration of the flea
β = 88.21°
