Answer:
1.#potential energy = PE, m = mass in kg, g = force of gravity, h= vertical height above the ground. ** means to the power of ie exponent. * means multiply.
PE = mgh
300 = m(10)(15)
m = 300/(10)(15)
m= 2kg
2. KE = 1/2 mv**2
= 1/2(50)(50)**2
= 2500 joules
Explanation
Is as in solution
Answer:
0.832
Explanation:
8.320 x 10 to the negative 1st power is 0.832
Answer:
I don't know sorry hopefully I can help with something else tho
Answer:
-1.24 m/s
Explanation:
Total momentum before collision = total momentum after collision
Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).
Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back 6 m/s (east), velocity of line back = -8 m/s (west). Hence:
Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s
The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.
Let velocity after collision be v, hence:
The total momentum after collision = (112 + 120)v = 232v
Total momentum before collision = total momentum after collision
-288 = 232v
v = -288 / 232
v = -1.24 m/s
Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).
