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2 years ago

X/3/8 = 24 put answer as whole number

Mathematics

1 answer:

rewona [7]2 years ago

8 0

Answer:

$9 = x$

Step-by-step explanation:

$24 = \frac{x}{\frac{3}{8}} \\ \\ [24][\frac{3}{8}] = \frac{72}{8} = 9 \\ \\ 9 = x$

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ZABD and ZDBC are supplementary angles.

IRINA_888 [86]

Answer:

the answer is 50

Step-by-step explanation:

180-130=50

4 0

2 years ago

Read 2 more answers

Solve the quadratic equation 4x2 − 121 = 0. Verify your answer using a difference-of-squares factoring method.

Alenkasestr [34]

Answer:

Option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

Step-by-step explanation:

Given quadratic equation is $4x^2-121=0$

To write the given quadratic equation by using a difference-of-squares factoring method:

$4x^2-121=0$

The above equation can be written as

$4x^2-11^2=0$

$(2x)^2-11^2=0$

The above equation is in the form of difference-of-squares

Therefore the given quadratic equation can be written in the form of difference-of-squares

by factoring method is $(2x)^2-11^2=0$

$(2x+11)(2x-11)=0$ (which is in the form $a^2-b^2=(a+b)(a-b)$ )

2x+11=0 or 2x-11=0

$x=\frac{-11}{2}$ or $2x=11$

$x=\frac{-11}{2}$ or $x=\frac{11}{2}$

$x=\pm \frac{11}{2}$

Therefore option d) is correct

That is x equals plus or minus start fraction 11 over two end fraction

5 0

2 years ago

Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے

Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

$A=\frac{8}{3} \sqrt{p h} \cdot h$

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

$\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\$

Generally, the equation for the Area is mathematically given as

$& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\$

$&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h$

$A=\frac{8}{3} \sqrt{p h} \cdot h$

In conclusion, the equation for the Area is

$A=\frac{8}{3} \sqrt{p h} \cdot h$