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Naily [24]
3 years ago
13

Calculate the number of photons having a wavelength of 12.0 μm required to produce 1.0 kJ of energy.

Chemistry
1 answer:
nika2105 [10]3 years ago
4 0

Answer:

N = 603.32 × 10 ²⁰

Explanation:

Given data:

Wavelength of photon = 12.0 μm or 12 × 10 ⁻⁶ m

Energy = 1.0 KJ  or 1000 j

Number of photons = ?

Solution:

Formula:

E  = n . h . f

E = energy

N = number of photons

h = planck's constant

f = frequency

it is known that

f = c/λ

thus,

E = N . h . c / λ

Now we will put the values in formula.

1000 j = ( N. 6.63 × 10 ⁻³⁴ j.s × 3 × 10⁸ m/s ) / 12 × 10 ⁻⁶ m

N = 1000 j ×12 × 10 ⁻⁶ m  / 6.63 × 10 ⁻³⁴ j.s × 3 × 10⁸ m/s

N = 12000 j × 10 ⁻⁶ m / 19.89 × 10 ⁻²⁶ j. m

N = 603.32 × 10 ²⁰

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Explanation:

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KMnO4-

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7 0
3 years ago
What mass of CaSO3 must have been present initially to produce 14.5 L of SO2 gas at a temperature of 12.5°C and a pressure of 1.
german
When the reaction equation is:

CaSO3(s) → CaO(s) + SO2(g)

we can see that the molar ratio between CaSO3 & SO2 is 1:1 so, we need to find first the moles SO2.

to get the moles of SO2 we are going to use the ideal gas equation:

PV = nRT

when P is the pressure =  1.1 atm

and V is the volume = 14.5 L 

n is the moles' number (which we need to calculate)

R ideal gas constant = 0.0821

and T is the temperature in Kelvin = 12.5 + 273 = 285.5 K

so, by substitution:

1.1 * 14.5 L = n * 0.0821 * 285.5

∴ n = 1.1 * 14.5 / (0.0821*285.5)

       = 0.68 moles SO2

∴ moles CaSO3 = 0.68 moles

so we can easily get the mass of CaSO3:

when mass = moles * molar mass

and we know that the molar mass of CaSO3= 40 + 32 + 16 * 3 = 120 g/mol


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7 0
3 years ago
Compounds can be broken down by using what method?
Dima020 [189]

Answer:

chemical change

Explanation:

chemical change requires energy in the form of heat or electricity.

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Answer:

D

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Which of the following statements is true concerning what happens when cold milk is poured into hot coffee?
liraira [26]

Answer:

The cold milk transfers its cold to the coffee, cooling the coffee down.

Hope This Helps!

6 0
3 years ago
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