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3 years ago

Which of the following best defines base isolation?(1 point)

1 answer:

3 0

Base isolation is a method of earthquake resistant engineering where a structure is separated from the ground by isolation units that reduces the impact of seismic vibration energy. So, the last answer choice would be the best definition.

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Match the salt with the acid and base used to form it in a neutralizing reaction.

nignag [31]

<h3><u>Answer;</u></h3>

K2SO4 - KOH and H2SO4

NaBr - NaOH and HBr

<h3><u>Explanation;</u></h3>

Salts are compounds that contain positively charged ions and negatively charged ions. That is; they consist of the positive ion of a base and the negative ion of an acid.
Salts may be produced when acids and bases are combined together in equal proportions, a process called neutralization.
During neutralization reactions an acid reacts with a base to form a salt and water as the only products.

4 0

2 years ago

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During the phase change from solid ice to liquid water, which bonds/forces are being weakened?

vampirchik [111]

I think Intramolecular forces are being weakened

5 0

2 years ago

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Separation of light into different wavelengths

TiliK225 [7]

Answer:

I'm sure it's Dispersion

Explanation:

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2 years ago

Maintenance of............of the body such as temperature level, water content, pH and blood pressure to be in balanced and stab

n200080 [17]

This is homeostasis of the body I believe.

6 0

2 years ago

A cubic piece of platinum metal (specific heat capacity = 0.1256 J/°C･g) at 200.0°C is dropped into 1.00 L of deuterium oxide ('

polet [3.4K]

Answer:

$a=5.65cm$

Explanation:

Hello,

In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

$Q_{Pt}=-Q_{Deu}$

We can represent the heats in terms of mass, heat capacities and temperatures:

$m_{Pt}Cp_{Pt}(T_f-T_{Pt})=-m_{Deu}Cp_{Deu}(T_f-T_{Deu})$

Thus, we solve for the mass of platinum:

$m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g$

Next, by using the density of platinum we compute the volume:

$V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3$

Which computed in terms of the edge length is:

$V=a^3$

Therefore, the edge length turns out:

$a=\sqrt[3]{180cm^3}\\ \\a=5.65cm$

Best regards.

6 0

3 years ago