Which of the following best defines base isolation?(1 point)
1 answer:
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Answer:
Explanation:
There are few simple rules in organic chemistry which a person must learn.
1. In predicting a structure from ozonolysis, number of oxygen present in products must be counted. In this particular example, there are 2+3+1 = 6 oxygen atoms are present in three molecules. This means that there should be at least three confirmed double bonds must be present in the molecule of Dictyopterene.
2. There are in total of 3+5+3 = 11 carbon atoms present, making 2^11 = 2048 possible structures for this particular structure. But since there are three double bonds present, this will reduce the number of possible structures as well.
3. Questions also says that when fully hydrogenated, the molecule generates Butylcycloheptane. That means that our base molecule is Butylcycloheptane and this molecule contains at least three double bonds.
So, first we draw the molecule of butylcycloheptane. After this, we think of were double bonds could be present. We do have the products. Let's make their structures first. I have also mentioned the possible breakup where the ozonolysis has occured by color code. You can see them in the reference image attached.
Part 1 out of 2: There is only one chiral carbon present in the molecule and have two possible isomers. Cis and Trans. Only one stereogenic carbon is present, that's why two possible isomers. Image attached.
Answer:
A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH
Explanation:
The pH of a buffer solution is calculated using following relation
Thus the pH of buffer solution will be near to the pKa of the acid used in making the buffer solution.
The pKa value of HC₃H₅O₃ acid is more closer to required pH = 4 than CH₃NH₃⁺ acid.
pKa = -log [Ka]
For HC₃H₅O₃
pKa = 3.1
For CH₃NH₃⁺
pKa = 10.64
pKb = 14-10.64 = 3.36 [Thus the pKb of this acid is also near to required pH value)
A mixture of 100. mL of 0.1 M HC3H5O3 and 50. mL of NaOH
Half of the acid will get neutralized by the given base and thus will result in equal concentration of both the weak acid and the salt making the pH just equal to the pKa value.