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Art [367]
3 years ago
12

Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 5

4.0 g of al react with 319 g of cuso4? al + 3cuso4 â al2(so4)3 + 3cu
Chemistry
1 answer:
exis [7]3 years ago
8 0
Answer is: 127 grams <span>rams of metallic copper can be obtained.
</span>Balanced chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54.0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 54 g ÷ 27 g/mol.
n(Al) = 2 mol.
m(CuSO₄) = 319 g.
n(CuSO₄) = 319 g ÷ 159.6 g/mol.
n(CuSO₄) = 2 mol; limiting reactant.
From chemical reaction: n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
n(Cu) = 2 mol · 63.55 g/mol.
n(Cu) = 127.1 g.
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7 0
3 years ago
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Why is calcium chloride (rock salt, CaCl2) more effective than sodium chloride (table salt, NaCl) at de-icing roads in the winte
Tema [17]

Answer:

The correct option is;

D. Calcium chloride breaks into 3 ions, while sodium chloride only breaks into 2 ions

Explanation:

To help melt the ice on icy streets, calcium chloride (CaCl₂) is a more preferred salt type to sodium chloride (NaCl) as when it dissociates into ions in the ice, it forms three ions: a calcium ion, Ca²⁺, and two chloride ions, 2 Cl⁻, while sodium chloride forms two ions: one sodium ion, Na⁺, and one chloride ion, Cl⁻

According to the freezing point depression equation, we have;

ΔT = K_f × m × i

Where;

ΔT = Change in freezing point temperature

K_f = The freezing point depression constant

m = The solution's molality

i = van't Hoff factor

The calcium chloride salt will cause the most depression because the van't Hoff factor is 3 for calcium chloride and 2 for sodium chloride.

7 0
3 years ago
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A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g ×\frac{1mol}{159,609g} = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g ×\frac{1mol}{18,02g} = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

5 0
3 years ago
Which binary molecular compound includes an element with five atoms of one element?
uranmaximum [27]

Answer:

For example, N2O4 is referred to as dinitrogen tetroxide, not dinitrogen tetraoxide, and CO is called carbon monoxide, not carbon monooxide.

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Binary molecular (covalent) compounds.

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prefix number of atoms

tetra- 4

penta- 5

hexa- 6

Explanation:

6 0
2 years ago
A 100.0g sample of nickel is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water a
Marianna [84]

Answer:

0.429 J/g.°C

Explanation:

Step 1: Calculate the heat absorbed by the water (Qw)

We will use the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in the temperature

Qw = 4.184 J/g.°C × 150. g × (29.8°C-25.0°C) = 3012 J

Step 2: Calculate the heat released by the sample of nickel

According to the law of conservation of energy, the sum of the heat lost by the sample of nickel and the heat absorbed by the water is zero.

Qw + QNi = 0

QNi = -Qw = -3012 J

Step 3: Calculate the specific heat capacity of nickel

We will use the following expression.

QNi = c × m × ΔT

c = QNi/m × ΔT

c = -3012 J/100.0 g × (29.8°C-100.0°C) = 0.429 J/g.°C

6 0
3 years ago
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