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Art [367]
3 years ago
12

Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 5

4.0 g of al react with 319 g of cuso4? al + 3cuso4 â al2(so4)3 + 3cu
Chemistry
1 answer:
exis [7]3 years ago
8 0
Answer is: 127 grams <span>rams of metallic copper can be obtained.
</span>Balanced chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54.0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 54 g ÷ 27 g/mol.
n(Al) = 2 mol.
m(CuSO₄) = 319 g.
n(CuSO₄) = 319 g ÷ 159.6 g/mol.
n(CuSO₄) = 2 mol; limiting reactant.
From chemical reaction: n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
n(Cu) = 2 mol · 63.55 g/mol.
n(Cu) = 127.1 g.
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4 0
3 years ago
The density of a 45.0 mass % solution of ethanol (C2H5OH) in water is 0.873 g/mL. What is the molarity of the solution?
antoniya [11.8K]

Answer : The concentration of solution is, 8.53 M.

Explanation :

As we are given, 45.0 mass % solution of ethanol in water that means 45.0 g of ethanol present in 100 g of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{0.873g/mL}=114.5mL

Now we have to calculate the molarity of solution.

Mass of C_2H_5OH = 45.0 g

Volume of solution = 114.5 mL

Molar mass of C_2H_5OH = 46.07 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }C_2H_5OH\times 1000}{\text{Molar mass of }C_2H_5OH\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{45.0g\times 1000}{46.07g/mole\times 114.5mL}=8.53mole/L=8.53M

Therefore, the concentration of solution is, 8.53 M.

6 0
3 years ago
¿ ppr que no podemos automedicarnos ,cuando pensamos q tenemos el virus del CIVD-19?
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Porque como tu no eres profesional en medicina, no sabes nada sobre las dosis de medicamentos ni de los efectos que pueden tener en tu cuerpo si se administran incorrectamente.

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gto

Explanation:

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3 years ago
If the value of kc at 25oc is 3.7108, and the equilibrium concentrations for n2 and h2 are 0.000105 m and 0.0000542 m, respectiv
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Equation of decomposition of ammonia:

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Euilibrium constant:

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As concentration of N2=0.000105, H2=0.0000542

so equation will become:

3.7=(NH3)^2/(0.000105)*(0.0000542)^3

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3 years ago
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