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Alchen [17]
4 years ago
8

Scientists are studying compounds in a newly discovered rain forest plant. the plant produces an unusual substance that local pe

ople from the area say acts as an anesthetic.
if another scientist tests the substance using iodine, which macromolecule is the scientist testing for?

a. lipid

b. carbohydrate

c. nucleic acid

d. protein

Chemistry
2 answers:
meriva4 years ago
6 0

the answer is B carbohydrates

HOPE THIS HELPS

Alla [95]4 years ago
6 0

Answer:

B. Carbohydrate! I'm from k12, if needed for others I can give the answers to the test

You might be interested in
If the enthalpy (∆H) is negative the reaction is ____________________.
vichka [17]
Exothermic i guess because delta h is negative
7 0
3 years ago
A galvanic cell at a temperature of 25.0°C is powered by the following redox reaction:
Vlada [557]

<u>Answer:</u> The cell voltage of the given chemical reaction is 2.74 V

<u>Explanation:</u>

For the given chemical reaction:

Sn^{2+}(aq.)+Ba(s)\rightarrow Ba^{2+}(aq.)+Sn(s)

Here, gold is getting reduced because it is gaining electrons and nickel is getting oxidized because it is loosing electrons.

<u>Oxidation half reaction:</u>  Ba(s)\rightarrow Ba^{2+}(aq.)+2e^-;E^o_{Ba^{2+}/Ba}=-2.90V

<u>Reduction half reaction:</u>  Sn^{2+}(aq.)+2e^-\rightarrow Sn(s);E^o_{Sn^{2+}/Sn}=-0.14V

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=-0.14-(-2.90)=2.76V

To calculate the EMF of the cell, we use the Nernst equation, which is:

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Sn^{2+}]}{[Ba^{2+}]}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = +2.76 V

n = number of electrons exchanged = 2

[Ba^{2+}]=5.15M

[Sn^{2+}]=1.59M

Putting values in above equation, we get:

E_{cell}=2.76-\frac{0.059}{2}\times \log(\frac{1.59}{5.15})\\\\E_{cell}=2.74V

Hence, the cell voltage of the given chemical reaction is 2.74 V

8 0
4 years ago
I didn't really understand the explanation, can it be broken down
pentagon [3]

Answer:

40.06

Explanation:

<u>(23 * 39) + (48 * 40) + (29 * 41)</u>

                   100

= 40.06

formula:

<u>(% of isotope A * mass of A) + (% of isotope B * mass of B) ......</u>

                                        100

                                                                                                               

4 0
3 years ago
Read 2 more answers
Suppose you wanted to dissolve 40.0 g NaOH in enough H2O to make 6.00 dm3 of solution
dezoksy [38]

Molarity of solution = 1.6 M

<h3>Further explanation</h3>

Given

40 g NaOH

6 L solution

Required

Steps to solve the problem of molarity

Solution

No additional information about the question.

If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)

But if you want to know the molarity of a solution, then

  • 1. we calculate the moles of NaOH

\tt mol=\dfrac{mass}{MW}

MW(molecular weight) of NaOH=

Ar Na+ Ar O + Ar H

23 + 16 + 1 = 40 g/mol

so mol NaOH :

\tt mol=\dfrac{40~g}{40~g/mol}=1~mol

  • 2. Molarity(M)

\tt M=\dfrac{n}{V}\\\\M=\dfrac{1}{6}\\\\M=0.16

5 0
3 years ago
A student carries out the same titration but uses an indicator instead of a pH meter. If the indicator changes color slightly pa
creativ13 [48]

Answer:

Too high a value

Explanation:

HA + NaOH ⟶ NaA +H₂O

If the student has gone slightly past the equivalence point, they have added too much base.

The moles of HA are directly proportional to the moles of NaOH, so the moles of acid that the student calculates will be too high.

The calculated concentration of acid will also be too high.

4 0
3 years ago
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