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Tom [10]
3 years ago
8

How do you find molecules????? asap please!!!​

Chemistry
1 answer:
Andru [333]3 years ago
7 0
To find molecules you multiply the number of miles by avogadro’s constant(6.02*10^23). If you have the number of grams you would convert grams to moles then moles to molecules
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A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper
natali 33 [55]

Answer:

<h2>Density = 8.96 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of copper = 89.6 g

volume = 10 cm³

Substitute the values into the above formula and solve

That's

Density =  \frac{89.6}{10}

We have the final answer as

<h3>Density = 8.96 g/cm³</h3>

Hope this helps you

7 0
3 years ago
Diethyl ether is produced from ethanol according to the following equation:
juin [17]
The balanced chemical equation is given as:

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

We are given the yield of  CH3CH2OCH2CH3 and the amount of ethanol to be used for the reaction. These values will be the starting point for the calculations.

Theoretical amount of product produced:
329 g CH3CH2OH ( 1 mol / 46.07 g ) ( 1 mol CH3CH2OCH2CH3 / 2 mol CH3CH2OH ) (74.12 g / mol ) = 264.66 g CH3CH2OCH2CH3 

% yield = .775 = actual yield / 264.66


actual yield = 205.11 g CH3CH2OCH2CH3
6 0
3 years ago
2 HCl + 1 Zn -&gt; 1 H2 + ZnCl2 what type of reaction is this
Salsk061 [2.6K]

Answer:

Single replacement reaction

Explanation:

3 0
3 years ago
15. transition metals has ____ valence electrons
Gemiola [76]

2 valence electrons

Explanation:

Most transition metals have 2 valence electrons. Valence electrons are the sum total of all the electrons in the highest energy level (principal quantum number n). Most transition metals have an electron configuration that is ns2(n−1)d , so those ns2 electrons are the valence electrons.

8 0
3 years ago
Michelle is trying to find the average atomic mass of a sample of an unknown
GREYUIT [131]

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

  • Abundance of isotope A (A%) = 59.34%
  • Mass of isotope A = 113.6459 amu
  • Mass of isotope B = 115.8488 amu
  • Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
  • Average atomic mass =?

The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

Thus, the average atomic mass of the sample is 114.54 amu

Learn more about isotope: brainly.com/question/25868336

3 0
2 years ago
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