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2 years ago

12

A. The potential energy of the products is greater than the potential energy of the reactants

1 answer:

igomit [66]2 years ago

5 0

Answer: im pretty sure it is b but a is also good i going to be honest it a multi chose and i ant good at those

Explanation:

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What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig

Mashutka [201]

Answer:

$P_H =2.86$

$c=1.4\times 10^{-4}$

Explanation:

first write the equilibrium equaion ,

$C_3H_6O_3$ ⇄ $C_3H_5O_3^{-} +H^{+}$

assuming degree of dissociation $\alpha$ =1/10;

and initial concentraion of $C_3H_6O_3$ =c;

At equlibrium ;

concentration of $C_3H_6O_3 = c-c\alpha$

$[C_3H_5O_3^{-} ]= c\alpha$

$[H^{+}] = c\alpha$

$K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}$

$\alpha$ is very small so $1-\alpha$ can be neglected

and equation is;

$K_a = {c\alpha \times \alpha}$

$[H^{+}] = c\alpha$ = $\frac{K_a}{\alpha}$

$P_H =- log[H^{+} ]$

$P_H =-logK_a + log\alpha$

$K_a =1.38\times10^{-4}$

$\alpha = \frac{1}{10}$

$P_H= 3.86-1$

$P_H =2.86$

composiion ;

$c=\frac{1}{\alpha} \times [H^{+}]$

$[H^{+}] =antilog(-P_H)$

$[H^{+} ] =0.0014$

$c=0.0014\times \frac{1}{10}$

$c=1.4\times 10^{-4}$

6 0

3 years ago

List the official SI units

Juli2301 [7.4K]

Answer:

The seven SI base units, which are comprised of:

Length - meter (m)

Time - second (s)

Amount of substance - mole (mole)

Electric current - ampere (A)

Temperature - kelvin (K)

Luminous intensity - candela (cd)

Mass - kilogram (kg)

Explanation:

7 0

3 years ago

Read 2 more answers

A naturally occurring oil co-distills with water to produce an oil/water distillate that is 20% oil by weight. If the molecular

Gelneren [198K]

Answer:

Explanation:

Partial pressure of oil = mole fraction of oil x total pressure

mole fraction of oil = mole of oil / mole of water + mole of oil

= mole of oil = mass of oil / molecular weight of oil

= 20 / 100 = .2

mole of water = 80 / 18

= 4.444

mole fraction of oil = .2 / .2 + 4.444

= .2 / 4.644

Partial pressure of oil = mole fraction of oil x total pressure

= (.2 / 4.644 ) x 760 mm

= 32.73 mm Hg .

3 0

3 years ago

If you were going to graphically determine the enthalpy of vaporization, δhvap, for this liquid, what points would you plot

Klio2033 [76]

It depends on what type of graph you have. The easiest would be using a H-T diagram. Enthalpy of vaporization is the physical change from liquid to vapor. It occurs at a constant pressure and a constant temperature. As shown in the picture, 1 point is drawn on the subcooled liquid, and another point of the saturated vapor isothermal line. Now, the difference between those two points is the value for the enthalpy of vaporization of water.

8 0

3 years ago

The area of a telescope lens is 7903 rnrn2 {a) What is the area in square feet (ft2)? (b) If it takes a technician 45 s to polis

LekaFEV [45]

Answer:

Area is 0.08504 $ft^{2}$ and $2.6\times 10^{3}s$ are needed for polishing

Explanation:

(a) ft is unit of F.P.S system whether mm is unit of M.K.S system.

According to unit conversion, $1mm=0.00328ft$

So, $1mm^{2}=(0.00328)^{2}ft^{2}=1.076\times 10^{-5}ft^{2}$

hence, $7903mm^{2}=7903\times 1.076\times 10^{-5}ft^{2}=0.08504ft^{2}$

So, area of telescope lens is 0.08504 $ft^{2}$

(b) $135mm^{2}$ are polished in 45s

So, $7903mm^{2}$ are polished in $\frac{45\times 7903}{135}s$ or $2.6\times 10^{3}s$

5 0

2 years ago