Explanation:
the correct empirical formula for C6H12O6 is CH2O...
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Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
The AZX symbol of a cation with 13 neutrons is A = 24 , Z = 11 and X = Na+
<h3>What is AZX?</h3>
AZX is a symbol which stands for;
- A is the mass number
- Z is the atomic number or the number of protons
- X is the chemical symbol of the element
Note, cations are positively-charged ions having more protons than electrons due to loss of one or more electrons.
Sodium ion represented as Na+ is a cation which lost one electron. It has 13 neutrons and 11 protons.
But the mass number of an element, A is the sum of protons and neutrons of the element.
Thus, for Na+
A = 13 + 11 = 24
Z = 11
X = Na+
Therefore, the AZX symbol of a cation with 13 neutrons is A = 24 , Z = 11 and X = Na+
Learn more about sodium ion here:
brainly.com/question/1933786
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Th actual yield of the reaction is 24.86 g
We'll begin by calculating the theoretical yield of the reaction.
2Na + Cl₂ → 2NaCl
Molar mass of Na = 23 g/mol
Mass of Na from the balanced equation = 2 × 23 = 46 g
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Mass of NaCl from the balanced = 2 × 58.5 = 117 g
From the balanced equation above,
46 g of Na reacted to produce 117 g of NaCl.
Therefore,
11.5 g of Na will react to produce = (11.5 × 117) / 46 = 29.25 g of NaCl.
Thus, the theoretical yield of NaCl is 29.25 g.
Finally, we shall determine the actual yield of NaCl.
- Theoretical yield = 29.25 g
Actual yield = Percent yield × Theoretical yield
Actual yield = 85% × 29.25
Actual yield = 0.85 × 29.25 g
Actual yield = 24.86 g
Learn more about stoichiometry: brainly.com/question/25899385
