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2 years ago

15 points Discuss how cells differ from one another

Chemistry

1 answer:

Sladkaya [172]2 years ago

5 0

Answer:

Cellular differentiation is the process in which a cell changes from one cell type to another. Usually, the cell changes to a more specialized type. Differentiation occurs numerous times during the development of a multicellular organism as it changes from a simple zygote to a complex system of tissues and cell types.

Explanation: from google

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The initial pressure and volume of a gas are 55.16 kilopascals and 0.500 liter. According to Boyle’s law, if the volume of the g

Gnesinka [82]

Answer: The final pressure is 34.48kPa

Initial Pressure P1 = 55.16kPa

Initial Volume V1 = 0.500L

Final Pressure P2 = ?

Final Volume V2 = 0.800L

Boyle's law P1V1 = P2 V2

P2 = P1V1/V2

P2 = 55.16*0.5/0.8

P2 = 34.48kPa

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3 years ago

Does money make the personality of person

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No, it doesn’t define a person, money doesn’t change people.

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2 years ago

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How could a change to the size of the algae population cause an increase in the size of the moon jelly population? (Be sure to d

timofeeve [1]

Answer:

The deaths of one species leaves room for another to grow. for example is there are not enough wolves to kill the deer the deer population will increase and that would start to cause problems. If there is not enough algae to combat the moon jelly the amount of moon jelly will increase because there is nothing to stop it.

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2 years ago

Classify each of these statements as always true, at; sometimes true, st; or never true, nt. 11. the rate at which a solute diss

photoshop1234 [79]

It is always true that the rate at which a solute dissolves can be increased by grinding. The smaller the solute the easier it will dissolve in the solvent, while other facts play into the rate at which a solute dissolves in a solvent, a major part of this is also how small the solute is. You can think of how rock salt is harder to dissolve in water compared to finely ground salt.

It is sometimes true that as the temperature of a solvent decreases, the solubility of a solute increase. The reason for this is that for liquids and solids as temperature increases the solubility increases but for gasses, as the temperature increases the solubility decreases.

It is always true that stirring a solute when adding it to a solvent should increase the rate of its dissolving. however, this will not increase the amount that is able to be dissolved in the solution.

It is never true that Henry's law states that the solubility of a gas in a liquid is a function of temperature. Henry's law is a gas law that was determined by William Henry in 1803. The law dictates that when in constant temperature the amount of gas that dissolves in a given volume of a liquid is proportional directly to the partial pressure of the gas at equilibrium with the desired liquid. In simpler terms, the solubility of the gas in a certain liquid is proportional to the partial pressure of the gas above the liquid.

It is always true that two liquids that dissolve in each other are miscible. Miscibility is described as the property of liquids and other substances to mix in all proportions and forming homogeneous solutions.

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3 years ago

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2

Rina8888 [55]

Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.

Answer 1) σ Bond a : C has $SP^{2}$ O has $SP^{2}$ .

Explanation : The orbitals of oxygen and carbon which are involved in $SP^{2}$ hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.

Answer 2) π Bond a: C has π orbitals and O also has π orbitals.

Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.

Answer 3) Bond b: O $SP^{3}$ H has only S orbital involved in bonding.

Explanation : The bonding at 'b' position involves oxygen $SP^{3}$ hydrogen atoms in it. It has $SP^{3}$ hybridized orbitals and S orbital of hydrogen involved in the bonding.

Answer 4) Bond c: C is $SP^{3}$ O is also $SP^{3}$

Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of $SP^{3}$ hybridized bonds.

Answer 5) Bond d: C atom has $SP^{3}$ C atom has $SP^{3}$

Explanation : At the position of 'd' the bonding between two carbon atoms is found to be $SP^{3}$ . Therefore, the orbitals that undergo $SP^{3}$ hybridization are $SP^{3}$ .

Answer 6) Bond e : C1 containing O $SP^{2}$

C2 is $SP^{3}$

Explanation : The carbon atom which contains oxygen along with a double bond has $SP^{2}$ hybridized orbitals involved in the bonding process; whereas the carbon at C2 has $SP^{3}$ hybridized orbitals involved during the bonding. This is for the 'e' position.

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3 years ago