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AleksAgata [21]
3 years ago
9

What was Anton van Lee

Chemistry
1 answer:
solniwko [45]3 years ago
5 0

I would say the answer is A.

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I need help on science lol.
Anit [1.1K]

Answer:

yes your right its is 4

Explanation:

6 0
3 years ago
Read 2 more answers
An ethylene glycol solution contains 16.2 g of ethylene glycol (c2h6o2) in 85.4 ml of water. calculate the boiling point of the
Andre45 [30]
<span>Answer: (16.2 g C2H6O2) / (62.0678 g C2H6O2/mol) / (0.0982 kg) = 3.9704 mol/kg = 3.9704 m a.) (3.9704 m) x (1.86 °C/m) = 7.38 °C change 0.00°C - 7.38 °C = - 7.38 °C b.) (3.9704 m) x (0.512 °C/m) = 2.03 °C change 100.00°C + 2.03 °C = 102.03 °C</span>
7 0
4 years ago
What is the relationship between the word pairs in this analogy? dull: boring as amusing: entertaining O A. Synonyms O B. Antony
leva [86]

Answer:

A: Synonyms

Explanation:

Synonyms are two words that have same meaning but are different words (tell me if this works!)

8 0
3 years ago
Read 2 more answers
In the reaction 2co ( g) + o2( g) → 2co2( g), what is the ratio of moles of oxygen used to moles of co2produced?
KIM [24]
In the reaction 2co ( g) + o2( g) → 2co2( g), the ratio of moles of oxygen used to moles of co2produced is 1:2.
8 0
3 years ago
How much heat is gained when a 50.32g piece of aluminum is heated from 9.0°c to 16°c
Rashid [163]

Answer: 317 joules

Explanation:

The quantity of heat energy (Q) gained by aluminium depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

In this case,

Q = ?

Mass of aluminium = 50.32g

C = 0.90J/g°C

Φ = (Final temperature - Initial temperature)

= 16°C - 9°C = 7°C

Then, Q = MCΦ

Q = 50.32g x 0.90J/g°C x 7°C

Q = 317 joules

Thus, 317 joules of heat is gained.

5 0
4 years ago
Read 2 more answers
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