Hey!!
here is your answer >>>>
If there are 8 students, and who have 3/4 the cake to share equally, we will have to divide 3/4 with 8.
which is( 3/4)/(8)
Now, we will have to take a reciprocal, we get,
(3/4)(1/8)
which is 3/32
which is
Each student gets, 3/32 of the cake!
Hope my answer helps!
So just add 1/8 and 2/8. add 1 plus 2 and the denominator (bottom number) stays the same so you get 3/8 then subtract 8/8 minus 3/8 so just 8 minus 3 is 5 and the denominator stays the same so you end up with 5/8 so 5/8 of the book remains unread
Answer:
The correct option is (C).
Step-by-step explanation:
According to the Central Limit Theorem if we have n unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.
Then, the mean of the distribution of sample means is given by,
![\mu_{\bar x}=\mu](https://tex.z-dn.net/?f=%5Cmu_%7B%5Cbar%20x%7D%3D%5Cmu)
And the standard deviation of the distribution of sample means is given by,
![\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Csigma_%7B%5Cbar%20x%7D%3D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
The information provided is:
<em>μ</em> = 3.5
<em>σ</em> = 1.7078
<em>n</em> = 400 = number of times the experiment is repeated.
As the sample size is quite large, i.e. <em>n</em> = 400 > 30 the central limit theorem can be used to approximate the sampling distribution of the sample mean.
The mean of the distribution of sample means is:
![\mu_{\bar x}=\mu=3.5](https://tex.z-dn.net/?f=%5Cmu_%7B%5Cbar%20x%7D%3D%5Cmu%3D3.5)
The standard deviation of the distribution of sample mean is:
![\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{1.7078}{\sqrt{400}}=0.0854](https://tex.z-dn.net/?f=%5Csigma_%7B%5Cbar%20x%7D%3D%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%3D%5Cfrac%7B1.7078%7D%7B%5Csqrt%7B400%7D%7D%3D0.0854)
The distribution of the sample mean is:
.
Thus, the correct option is (C).
Answer:
Step-by-step explanation:
I know this is from Khan Academy, can you please try to copy the question so it will be easier to read?
The given angles mean that line QT divides angle PQS.
<em>The measure of </em>
<em> is </em>
<em />
Given that:
![\angle PQS = 3x + 13](https://tex.z-dn.net/?f=%5Cangle%20PQS%20%3D%203x%20%2B%2013)
![\angle SQT = 6x -2](https://tex.z-dn.net/?f=%5Cangle%20SQT%20%3D%206x%20-2)
Since QT divides
;
The equation to calculate
is:
![\angle PQT = \angle PQS - \angle SQT](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%20%5Cangle%20PQS%20-%20%5Cangle%20SQT)
This gives
![\angle PQT = 3x + 13- (6x -2)](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%203x%20%2B%2013-%20%286x%20-2%29)
Open bracket
![\angle PQT = 3x + 13- 6x +2](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%203x%20%2B%2013-%206x%20%2B2)
Collect like terms
![\angle PQT = 13+2- 6x + 3x](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%2013%2B2-%206x%20%2B%203x)
![\angle PQT = 15- 3x](https://tex.z-dn.net/?f=%5Cangle%20PQT%20%3D%2015-%20%203x)
Hence, the measure of
is ![15- 3x](https://tex.z-dn.net/?f=15-%20%203x)
Read more about angles at:
brainly.com/question/13954458