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3 years ago

10

Simplify. 8 - [ - ( -3)]

2 answers:

ICE Princess25 [194]3 years ago

6 0

$8 - [ - ( -3)]$ $(- + - = +)$

$8+3$

$=11$

lesya [120]3 years ago

3 0

I think the answer is 11
the random negative shouldn't be turned into a positive therefore leaving the 3 negative

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Imagine a new pasture with grass growing on it. Every day after the seeds have germinated, the number of blades of grass in the

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Answer:

It took 17 days for the pasture to be one-third covered in grass

Step-by-step explanation:

* Lets explain how to solve the problem

- The number of blades of grass is triple every day

- Consider that there are x blades in the first day

∵ The number of blades of grass is triple every day

∴ The next day the number of blades of grass will be 3x

∴ The formula to find the number of blades of grass after d days is

$x(3)^{d}$

- After 18 days, the entire pasture is completely covered in grass

∵ d = 18

∴ The number of blades of grass = $x(3)^{18}$

- We need to know the the number of days that took for the pasture

to be one-third covered in grass

∵ The number of blades of grass for 1/3 covered = $(\frac{1}{3})x(3)^{18}$

∴ $(\frac{1}{3})x(3)^{18}=x(3)^{d}$

- Remember $\frac{1}{3}=3^{-1}$

∴ $3^{-1}x(3)^{18}=x(3)^{d}$

- Remember we add the power of the same bases when we

multiply them

∴ $x(3)^{-1+18}=x(3)^{d}$ ⇒ divide both sides by x

∴ $(3)^{17}=(3)^{d}$

- Remember if the two bases equal in the equation, then their

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∴ d = 17

* It took 17 days for the pasture to be one-third covered in grass

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4 years ago

The net of a cylinder is shown. The area of one base of the cylinder is 9Pi in.2. The circumference of a base is 6Pi in., and th

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Answer:

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Step-by-step explanation:

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4 years ago

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3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

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3 years ago