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3 years ago

What does it mean if an experiment exhibits reproducibility

Chemistry

1 answer:

Vladimir [108]3 years ago

4 0

Means that the procedures used in an experiment can be done in other settings giving the same results.

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Which of the following describes the correct order for using the scientific

larisa [96]

A. is the answer
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3 years ago

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How much faster does ethane (C2H6) gas travel compared to chlorine gas?

zimovet [89]

Answer:

$\large \boxed{\text{54 $\, \%$ faster }}$

Explanation:

$v_{\text{rms}} \propto \sqrt{\dfrac{3RT}{M}$

if temperature is constant.

$v_{\text{rms}} \propto \sqrt{\dfrac{1}{M}$

if we are comparing two gases,

$\dfrac{v_{2}}{v_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}$

Let chlorine be Gas 1 and ethane be Gas 2

Data:

M₁ = 70.91 g/mol

M₂ = 30.07 g/mol

Calculation

$\begin{array}{rcl}\dfrac{v_{2}}{v_{1}} & = & \sqrt{\dfrac{M_{1}}{M_{2}}}\\\\& = & \sqrt{\dfrac{70.91}{30.07}}\\\\& = & \sqrt{2.358}\\\\& = & \mathbf{1.54}\\\end{array}\\\text{Ethane molecules travel at 1.54 times the speed of chlorine molecules}\\\text{or $\large \boxed{\textbf{54 $\%$ faster }}$ than chlorine molecules}$

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3 years ago

Which type of wave cannot move without a medium in which to travel?

Zanzabum

sound wave cannot travel without a medium.

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3 years ago

Given the balanced equation below, how many moles of chromium are

fenix001 [56]

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3 years ago

Calculate the standard enthalpy change for the reaction at 25 ∘ C. Standard enthalpy of formation values can be found in this li

meriva

Answer:

The standard enthalpy change for the reaction at $25^{0}\textrm{C}$ is -2043.999kJ

Explanation:

Standard enthalpy change ( $\Delta H_{rxn}^{0}$ ) for the given reaction is expressed as:

$\Delta H_{rxn}^{0}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]$

Where $\Delta H_{f}^{0}$ refers standard enthalpy of formation

Plug in all the given values from literature in the above equation:

$\Delta H_{rxn}^{0}=[3mol\times (-393.509kJ/mol)]+[4mol\times (-241.818kJ/mol)]-[1mol\times (-103.8kJ/mol)]-[5mol\times (0kJ/mol)]=-2043.999kJ$

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3 years ago