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algol [13]
4 years ago
6

Sound waves are longitudinal waves and are also called _____ waves.

Chemistry
2 answers:
Katena32 [7]4 years ago
6 0

Answer:

transverse

Explanation:

Nesterboy [21]4 years ago
5 0
They are called transverse waves
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What is the pressure in a 5.00 L tank with 49.00 grams of oxygen gas at 350 K? ___atm
ziro4ka [17]

Answer:

The right answer is "8.81 atm".

Explanation:

Given:

V = 5.00 L

Mass = 4900 g

MW = 32 g/mol

T = 350 K

Now,

Number of moles will be:

n = \frac{Mass}{MW}

   =\frac{49.00}{32}

   =1.53125 \ mole

By using the ideal gas equation, we get

⇒ PV=nRT

or,

⇒    P=\frac{nRT}{V}

By substituting the values, we get

           =\frac{1.53125\times 0.0821\times 350}{5.00}

           =\frac{44.1}{5.00}

           =8.81 \ atm  

4 0
3 years ago
Check all items common to bases:
Leona [35]
The common to bases is
<span>e-OH-
according to the characteristics of Arrhenius bases.

An Arrhenius base is a substance that produces OH- or hydroxide ions when dissolved in water. An Arrhenius acid, on the other hand, produces H+ ions when dissolved in water.</span>
3 0
3 years ago
Read 2 more answers
How does a higher heat capacity affect the amount of time it takes for an object’s temperature to change?
marshall27 [118]
<span> An object with a high specific heat would change temperature more slowly than one with low specific heat. Water, for example has a very high specific heat so it requires a lot of energy to heat it up. It also takes a while for water to cool down because it holds that heat for a long time. <3</span>
5 0
4 years ago
What is the wavelength of a 2.80 Hz wave?
s2008m [1.1K]
I attached the working and the answer to the question below.

Please note that in the formula,  C = speed of light, ν = frequency, λ= wavelength
<span>
The wavelength of a 2.80 Hz wave is 1.07 </span>× 10¹⁰ cm.


6 0
3 years ago
At high temperatures, carbon reacts with O2 to produce CO as follows: C(s) O2(g) 2CO(g). When 0.350 mol of O2 and excess carbon
777dan777 [17]

Answer:

Value of K_{c} is 0.090.

Explanation:

Initial molarity of O_{2} = \frac{0.350}{5.00}M = 0.0700 M

Construct an ICE table corresponding to the combustion reaction of carbon to determine K_{c}

                       C(s)+O_{2}(g)\rightarrow 2CO(g)

              I (M):    -      0.0700        0

             C (M):  -          -x             +2x

             E (M):   -    0.0700-x       2x

So, K_{c}=\frac{[CO]^{2}}{[O_{2}]}  , where [CO] and [O_{2}] represents equilibrium concentration of CO and O_{2} respectively.

Here, [CO]=2x=0.060

       ⇒x = 0.030

So, [O_{2}] = 0.0700-x = (0.0700-0.030) = 0.040

Hence,  K_{c}=\frac{(0.060)^{2}}{0.040}=0.090

4 0
3 years ago
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