All categories

2 years ago

A sample of carbon dioxide at RTP is 0.50 dm3. How many grams of carbon dioxide do we have?

Chemistry

1 answer:

prohojiy [21]2 years ago

3 0

Answer:

0.924 g

Explanation:

The following data were obtained from the question:

Volume of CO2 at RTP = 0.50 dm³

Mass of CO2 =?

Next, we shall determine the number of mole of CO2 that occupied 0.50 dm³ at RTP (room temperature and pressure). This can be obtained as follow:

1 mole of gas = 24 dm³ at RTP

Thus,

1 mole of CO2 occupies 24 dm³ at RTP.

Therefore, Xmol of CO2 will occupy 0.50 dm³ at RTP i.e

Xmol of CO2 = 0.5 /24

Xmol of CO2 = 0.021 mole

Thus, 0.021 mole of CO2 occupied 0.5 dm³ at RTP.

Finally, we shall determine the mass of CO2 as follow:

Mole of CO2 = 0.021 mole

Molar mass of CO2 = 12 + (2×16) = 13 + 32 = 44 g/mol

Mass of CO2 =?

Mole = mass /Molar mass

0.021 = mass of CO2 /44

Cross multiply

Mass of CO2 = 0.021 × 44

Mass of CO2 = 0.924 g.

You might be interested in

Lead is malleable, so it can be pounded into flat sheets without breaking. How does the bonding within lead help to explain this

damaskus [11]

Answer:

correct answer would be c

8 0

2 years ago

Convert the following to moles.

Luda [366]

Use dimensional analysis.
$\frac{60.0 grams NaOH}{1} * \frac{1 mole NaOH}{40.0 amu NaOH} =1.5 moles$

$\frac{2.73 grams NH4Cl}{1} * \frac{1 mole NH4Cl}{53.49 amu NH4Cl} = .051 moles$

Now you try converting moles to grams. All you have to do is start with MOLES (Unlike the previous examples) over 1 then multiply that ratio by the ratio of molar mass over 1 mole. Hope this helps!

6 0

2 years ago

How does cohesion affect the evaporation rate of water

wariber [46]

Answer:

Evaporation occurs because among the molecules near the surface of the liquid there are always some with enough heat energy to overcome the cohesion of their neighbors and escape. At higher temperatures the number of energetic molecules is greater, and evaporation is more rapid.

8 0

2 years ago

Ammonia, nh3, for fertilizer is made by causing hydrogen and nitrogen to react at high temperature and pressure. How many moles

charle [14.2K]

Answer:

$0.30molNH_3$

Explanation:

Hello there!

In this case, since the reaction for the formation of ammonia is:

$3H_2+N_2\rightarrow 2NH_3$

We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:

$0.15molN_2*\frac{2molNH_3}{1molN_2}$

And the result is:

$0.30molNH_3$

Best regards!

7 0

2 years ago

One reaction that destroys o3 molecules in the stratosphere is

Sidana [21]

One reaction that destroys o3 molecules in the stratosphere is when an ozone molecule combines with an oxygen atom to form two oxygen molecules, or through certain chemical reactions involving molecules containing hydrogen, nitrogen, chlorine, or bromine atoms. The atmosphere maintains a natural balance between ozone formation and destruction.

7 0

2 years ago