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Bingel [31]
4 years ago
7

The molar mass of the hydrated sodium sulfate is 322.1 g/mole. What is the formula of the hydrate salt?

Chemistry
1 answer:
garri49 [273]4 years ago
4 0

Answer:

Na₂SO₄·10H₂O.

Explanation:

Hello.

In this case, since the anhydrous sodium sulfate is:

Na_2SO_4

Whose molar mass is:

M=23+32+16*4=142 g/mol

But the total hydrate's molar mass is 322.1 g/mol, we can compute the mass of water:

m_{water}=322.1-142=180.1g/mol

Thus, the molecules of water are found by diving the total mass of water by the mass of one mole of water:

#water=\frac{180.1}{18}=10

It means, that the formula is Na₂SO₄·10H₂O.

Best regards.

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Answer:

option D= volcanoes

Explanation:

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2. In the form of glass obsidian are unstable and start to crystallize.

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4. older obsidian can not be found because these glassy rocks destroyed very rapidly.

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Pumice:

pumice is volcanic rock. it is formed from the lava having high amount of gases and water content. the gas escape and frothy lava cool very rapidly and form very lighter rock material, called pumice.

1. it is lighter in color because of high content of silica.

2. its crushing material produce fine powder, called volcanic ash.

3. its density is very low that's way it floats on the surface of water.

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6 0
3 years ago
when particles of matter are in direct contact and movement occurs in the substance due to convection, thermal energy transfers
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3 years ago
What is the radioactivity of the sample of sodium -24 after 30h?
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5 0
3 years ago
Read 2 more answers
Two iron bolts of equal mass—one at 100.°C, the other at 55°C—are placed in an insulated container. Assuming the heat capacity o
BARSIC [14]

The final temperature inside the container is 77.5°C

<h3>Solution ; </h3>

There are two heat transfers involved:

heat lost by bolt 1 + heat gained by bolt 2 = 0

-q(heat released by iron bolt) at higher temperature = q(heat gained by iron bolt) at lower temperature

-(cm)(T2-Treat higher temperature) = (cm)(T2-Tre at lower temperature)

-[0.450/(J/g-K) × m × (T2 -100°C)] = [0.450/(J/g-K) × m × (T2 -55°C)]

Or, -(T2 - 100°C) (T2 - 55°C) T2+T2 = 100°C + 55°C

Or, T2 = 155°C /2 = 77.5°C

<h3>What is Specific Heat ?</h3>

Specific heat is the amount of heat necessary to increase the temperature of one gram of a substance by one degree Celsius. Specific heat is often measured in calories or joules per gram per Celsius degree. Water, for example, has a specific heat of one calorie (or 4.186 joules) per gram per Celsius degree.

To know more about Specific Heat please click here : brainly.com/question/21406849

#SPJ4

4 0
2 years ago
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