What types of intermolecular forces are found in CH 4

Create a story and describe the motion (in meters) of an object that has traveled a distance but has no displacement.

aleksley [76]

Answer:

Circular motion

Explanation:

Consider a car race, where you need to finish one lap in a circuit. Her the start line and the finish line are the same. So , where you start, is where you will be reaching after the race is done. So, the displacement here is Zero , since displacement is the distance from initial point to final point. But, as one can see, the distance travelled is not zero.

Say the race track is a circle of radius r meters. So the lap distance would be the circumference of the circle, which is 2πr m. So the distance travelled is 2πr m and the displacement is zero.

Hope this satisfies you :)

7 0

3 years ago

List the number of each type of atom on the right side of the equation h2so4(aq)+bacl2(aq)→baso4(s)+2hcl(aq) enter your answers

DiKsa [7]

Answer is: 2H, 1S, 4O, 1Ba, 2Cl or 2,1,4,1,2.
Number of atoms must be the same on left and right side of balanced chemical reaction according to the law of conservation of mass or principle of mass conservation.
There are two hydrogen atoms, one sulfur atom, four oxygen atoms, one barium atom and two chlorine atoms in this chemical reaction.

3 0

3 years ago

A sample of a gas in a 4L container at 300K has a pressure of 1 atm. If the

zavuch27 [327]

The final pressure of the gas in the container is 4 atm

From the question given above, the following data were obtained:

Initial volume (V₁) = 4 L

Initial temperature (T₁) = 300 K

Initial pressure (P₁) = 1 atm

Final temperature (T₂) = 600 K

Final volume (V₂) = 2 L

<h3>Final pressure (P₂) =?</h3>

Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:

$\frac{P_{1} V_{1} }{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}\\\\\frac{1 * 4}{300} = \frac{P_{2} * 2}{600} \\\\$

Cross multiply

300 × 2 × P₂ = 4 × 600

600 × P₂ = 2400

Divide both side by 600

$P_{2} = \frac{2400}{600} \\\\$

Therefore, the final pressure of gas is 4 atm.

Learn more: brainly.com/question/23558057

4 0

3 years ago

A sample of nitrosyl bromide (nobr) decomposes according to the equation 2nobr(g)⇌2no(g)+br2(g) an equilibrium mixture in a 5.00

Alex73 [517]

Answer:

Kc = 0.122.

Explanation:

We can calculate Kc from the relation: Kc = [NO]².[Br₂] / [NOBr]².

Firstly, we convert the number of grams of each component to moles using (n = mass / molar mass).

n of NOBr = (3.26 g / 109.8 g/mole) = 0.03 moles.

n of NO = (3.06 g / 29.9 g/mole) = 0.102 moles.

n of Br₂ = (8.15 g / 159.9 g/mole) = 0.051 moles.

Then we can get the concentration of each component by dividing its no. of moles by the volume of the vessel (concentration = n / V).

The concentration of NOBr = (0.03 mole / 5.00 L) = 6x10⁻³ mol/L.

The concentration of NO = (0.102 mole / 5.00 L) = 2x10⁻² mol/L.

The concentration of Br₂ = (0.051 mole / 5.00 L) = 1x10⁻² mol/L.

Now, we can get Kc:

Kc = [NO]².[Br₂] / [NOBr]² = (2x10⁻² mol/L)².(1x10⁻² mol/L) / (6x10⁻³ mol/L)² = 0.122.

7 0

4 years ago

How many moles of CO2 are produced when 3.3 moles of C2H2 react

xxTIMURxx [149]

To solve this exercise you need to know that to create CO₂ with C₂H₂ is necessary to have oxygen. So, the following balanced equation represents the reaction:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)

Notice that 2 moles of C₂H₂ form 4 moles of CO₂, so if 3.3 moles of C₂H₂ react, how many moles of CO2 would be produced?
2 moles of C₂H₂ -------4 moles of CO₂
3.3 moles of C₂H₂--------x moles of CO₂
x=6.6 moles of CO₂ produced.

5 0

4 years ago