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Maurinko [17]
3 years ago
10

When comparing an x-ray to a radio wave, what should you look for to determine which formula represents the x-ray?

Physics
2 answers:
asambeis [7]3 years ago
7 0

Answer:

D. A low lambda, λ, and a high nu, ν

Explanation:

  • Both x-rays and radio waves are electromagnetic waves that are part of the electromagnetic spectrum.
  • <em><u>Radio waves have the longest wavelengths in the electromagnetic spectrum and the lowest frequency.</u></em>
  • X-rays on the other hand <em><u>have a higher frequency compared to radio waves and a lower wavelength than that of the radio waves</u></em>.
  • All electromagnetic waves in the electromagnetic waves travel with a speed of light, 3.0 × 10^8 m/s. They also posses energy given by the formula E = hf, where h is the plank's constant.
Blizzard [7]3 years ago
3 0

Answer:

it's D

Explanation:

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Okay i'm totally stuck and nobody I know really gets it either, so i've turned to Yahoo for help :)
OlgaM077 [116]

Here is the rule for see-saws here on Earth, and there is no reason
to expect that it doesn't work exactly the same anywhere else:

                     (weight) x (distance from the pivot) <u>on one side</u>
is equal to
                     (weight) x (distance from the pivot) <u>on the other side</u>.

That's why, when Dad and Tiny Tommy get on the see-saw, Dad sits
closer to the pivot and Tiny Tommy sits farther away from it.

       (Dad's weight) x (short length) = (Tiny Tommy's weight) x (longer length).


So now we come to the strange beings on the alien planet.
There are three choices right away that both work:

<u>#1).</u>
(400 N) in the middle-seat, facing (200 N) in the end-seat.

       (400) x (1)  =    (200) x (2)

<u>#2).</u>
(200 N) in the middle-seat, facing (100 N) in the end-seat.

       (200) x (1)  =    (100) x (2)

<u>#3).</u>

On one side:  (300 N) in the end-seat       (300) x (2) = <u>600</u>

On the other side:
                      (400 N) in the middle-seat  (400) x (1) = 400
           and     (100 N) in the end-seat      (100) x (2) = 200
                                                    Total . . . . . . . . . . . . <u>600</u> 


These are the only ones to be identified at Harvard . . . . . . .
There may be many others but they haven't been discarvard.


5 0
3 years ago
Read 2 more answers
I really need help.
Zielflug [23.3K]
2/5 = .4
.4*100= 40%
Alex spends more time
4 0
3 years ago
What is it about copper that makes it a good conductor
natta225 [31]
It’s because conductors have nearly zero resistance to the flow of electrons that go through them. This leaves the electrons free to move and current can travel with full strength.
6 0
2 years ago
Read 2 more answers
Satellites can focus on specific latitudes using:
Fittoniya [83]
B- east west orbits
4 0
2 years ago
Ballistic data obtained on a firing range show that aerodynamic drag reduces the speed of a .44 magnum revolver bullet from 250
m_a_m_a [10]

Answer:

0.363999909622

Explanation:

F = Force

m = Mass = 15.6 g

C = Drag coefficient

ρ = Density of air = 1.21 kg/m³

A = Surface area = \dfrac{\pi}{4}d^2

v = Terminal velocity = v=210\ m/s

s = Displacement = 150 m

a=\dfrac{v^2-u^2}{2s}

Force is given by

F = ma

F=\dfrac{1}{2}\rho CAv^2\\\Rightarrow ma=\dfrac{1}{2}\rho CAv^2\\\Rightarrow m\dfrac{v^2-u^2}{2s}=\dfrac{1}{2}\rho CAv^2\\\Rightarrow C=2\times m\dfrac{v^2-u^2}{2s}\times\dfrac{1}{\rho Av^2}\\\Rightarrow C=2\times15.6\times 10^{-3}\dfrac{210^2-250^2}{2\times 150}\times\dfrac{1}{1.21\times\dfrac{\pi}{4}\times (11.2\times 10^{-3})^2(210)^2}\\\Rightarrow C=-0.363999909622

The drag coefficient is 0.363999909622 (ignoring negative sign)

4 0
3 years ago
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