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Stolb23 [73]
3 years ago
6

Does oxygen have a greater mass than chlorine

Chemistry
1 answer:
rjkz [21]3 years ago
5 0
Atomic oxygen does not have a greater atomic mass than chlorine, nor does molecular oxygen.

Hope this help...


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A compound is found to contain 6.360 % silicon, 36.18 % bromine, and 57.46 % iodine by mass. what is the empirical formula for t
Karolina [17]
<span>Percentage of the compound,
 silicon = 6.360 %
 bromine = 36.18 %
 iodine = 57.46 %
 In 100 grams of compound we will have silicon = 6.36, bromine = 36.18, iodine = 57.46
 Molar mass
 silicon = 28.09, bromine = 79.90, iodine = 126.09
Calculating the moles,
 silicon = 6.36 / 28.09 = 0.226
 bromine = 36.18 / 79.90 = 0.452
 iodine = 57.46 / 126.09 = 0.455
 Divide with the lowest
 silicon = 0.226 / 0.226 = 1
 bromine = 0.452 / 0.226 = 2
 iodine = 0.455 / 0.226 = 2
 So the empirical formula would be SiBr2I2</span><span />
7 0
3 years ago
When a piece of metal mass of 54.52 g is dropped into a graduated cylinder containing 23.44 mL of water, the water level rises t
GaryK [48]

Answer:

<h2>Density = 10.01 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question

mass of metal = 54.52 g

Volume of metal = new volume - original volume of water in the cylinder

That's

new volume = 28.85 mL

original volume of water = 23.44 mL

Volume of metal

= 28.85 - 23.44 = 5.41 mL

Next we convert the volume from mL to cm³

1 mL = 1 cm³

5.41 mL = 5.41 cm³

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{54.52}{5 .41}   \\  = 10.07763</h3>

We have the final answer as

<h3>Density = 10.01 g/cm³</h3>

Hope this helps you

6 0
4 years ago
Is it possible for a population with a high birth rate to decrease in size? explain
mestny [16]
Yes, it is possible if the death rate exceeds that of the birth rate. This death rate could be due to a dramatic change in climate, health issues in a population, etc.
8 0
3 years ago
Please help me complete the following word equations:) also write the balanced equation, full ionic equation, and net ionic equa
AVprozaik [17]

Explanation:

The states may differ depending on the reactions

6 0
3 years ago
C. If 62.9 g of lead (II) chloride is produced, how many grams of lead (II) nitrate were
melomori [17]

Answer:

Mass = 76.176 g

Explanation:

Given data:

Mass of lead(II) chloride produced = 62.9 g

Mass of lead(II) nitrate used = ?

Solution:

Chemical equation:

Pb(NO₃)₂  +  2HCl     →     PbCl₂ + 2HNO₃

Number of moles of lead(II) chloride:

Number of moles = mass/molar mass

Number  of moles = 62.9 g/ 278.1 g/mol

Number of moles = 0.23 mol

Now we will compare the moles of lead(II) chloride with Pb(NO₃)₂ from balance chemical equation:

                            PbCl₂        :          Pb(NO₃)₂

                               1             :             1

                             0.23         :            0.23

Mass of Pb(NO₃)₂:

Mass = number of moles ×  molar mass

Mass = 0.23 mol × 331.2 g/mol

Mass = 76.176 g

8 0
4 years ago
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