MH₂ = 2×mH = 2×1g = 2 g/mol
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
Explanation:
To solve this problem, we need to understand the concept of precision and accuracy.
Through this understanding we apply to solve this problem.
- Precision is the ability to reproduce the same set of values in an experiment.
- Accuracy is the nearness or closeness of the measured value to the true value.
For example; if the true value is 28.0mm and the following readings were made:
A = 24.0mm, 24.0mm, 24.3mm, 23.9mm This is a precise measurement but not accurate.
B = 27.9mm, 28.0mm, 28.1mm: This is an accurate measurement because it is close to the true value.
Answer:
You can see that it is an endothermic reaction or heat is being absorbed for the change from magnesium to magnesium oxide. So it is an endothermic reaction. So these are the four reasons why we can say that burning of magnesium ribbon in the air is considered a chemical change.
Explanation:
hope it help
