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Katen [24]
4 years ago
13

3x^2+7x+2 how to factor​

Mathematics
2 answers:
Hunter-Best [27]4 years ago
6 0

Work is attached in the image provided.

For your second pair of binomials, (3x + 1)(x + 2), the product of the outer terms is 6x and the product of the inner terms is 1x and 6x + 1x = 7x which is the middle term in you're original trinomial.

So the second pair of binomials represents your answer.

AVprozaik [17]4 years ago
3 0

3 {x}^{2}  + 7x + 2 \\  = 3 {x}^{2}  + 6x + x + 2 \\  = 3x(x + 2) + 1(x + 2) \\  = (3x + 1)(x + 2)

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Please help me with this question
boyakko [2]

Answer:

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Step-by-step explanation:

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sin(53.13) = 0.7999989281

5 0
3 years ago
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3 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

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P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

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P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

18+3m+3n=0

3m+3n=-18

Divide both sides by 3.

\dfrac{3m+3n}{3}=\dfrac{-18}{3}

m+n=-6

Hence proved.

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3 years ago
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gavmur [86]

Answer:y=-y

Step-by-step explanation:

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