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Hatshy [7]
3 years ago
7

Please answer this question :)

Mathematics
2 answers:
Otrada [13]3 years ago
6 0
5.27. I rounded the number cuz if not, it would have gave me a big #.
Scorpion4ik [409]3 years ago
5 0

Answer:

5.2692307692307692307692307692308

Step-by-step explanation:

hope this helps!  :)

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How do you solve for a triangle inside a circle (45 45 90 degree)
11111nata11111 [884]
I found this to help u if not here's the link: https://math.wonderhowto.com/how-to/prove-triangle-inscribed-circle-is-right-angled-340340/

it has a video to show u how to do it

7 0
3 years ago
First derivative of <br>√{cosec2x).show with full step.​
Mice21 [21]

Answer:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

Step-by-step explanation:

we are given a derivative

\displaystyle \:  \frac{d}{dx} ( \sqrt{  \csc(2x) } )

and said to figure out the first derivative

to do so

recall chain rule:

\sf\displaystyle \:  \frac{d}{dx} (f(g(x)) =  \frac{d}{dg} (f(g(x)) \times  \frac{d}{dx} (g)

so we get

\displaystyle \: g(x) =  \csc(2x)

rewrite the derivative using the chain rule:

\displaystyle \:  \frac{d}{dg} ( \sqrt{  g } )  \times  \frac{d}{dx} ( \csc(2x) )

use square root derivative rule to simplify:

\displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dx} ( \csc(2x) )

now we need to again use chain rule composite function derivative to simplify

where we'll take a new function n so we won't mess up two g's and we'll take 2x as n

use composite function derivative to simplify:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times  \frac{d}{dn}( \csc(n) ) \times  \frac{d}{dx} (2x)

use derivative formula to simplify derivatives:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - \cot(n)   \csc(n)  \times  2

substitute the value of n:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{g} }  \times   - 2\cot(2x)   \csc(2x)

substitute the value of g:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2\cot(2x)   \csc(2x)

now we need our trigonometric skills to simplify

rewrite cot and csc:

\sf \displaystyle \:   \frac{1}{ 2\sqrt{ \csc(2x) } }  \times   - 2 \dfrac{ \cos(2x) }{ \sin(2x) }   \dfrac{1}{ \sin(2x) }

simplify multiplication:

\sf \displaystyle \:   \frac{1}{ \cancel{ \:  2}\sqrt{ \csc(2x) } }  \times    \cancel{- 2} \dfrac{ \cos(2x) }{ \sin ^{2} (2x) }

simplify multiplication:

- \sf \displaystyle \:   \frac{ \cos(2x) }{ \sin ^{2} (2x)\sqrt{ \csc(2x) } }

4 0
3 years ago
Read 2 more answers
To solve the equation 2x−3=3x−7 , Esin graphs the functions f(x)=2x−3 and g(x)=3x−7 on the same set of coordinate axes.
Alecsey [184]
We have that

<span>f(x)=2x−3
g(x)=3x−7

2x-3=3x-7-------------> 3x-2x=-3+7-------> x=4 
find the value of f(x) or g(x) for x=4
</span>f(x)=2x−3 ------->  f(4)=2*4-3------> f(4)=5
<span>the solution is the point (4,5)

using a graph tool
see the attached figure

</span><span>statement

case a) </span><span>The solution of the equation cannot be found graphically. Esin should solve the equation algebraically.
this is not correct

case b) </span><span>The solution of the equation is the y-intercept of the linear equations.
</span>this is not correct

case c)<span>The solution of the equation is the x-coordinate of the ordered pair where the graphs of the two functions intersect.
</span>this is correct

case d) <span>The solution of the equation is the y-coordinate of the ordered pair where the graphs of the two functions intersect
this is not correct

the answer is 
</span>case c) The solution of the equation is the x-coordinate of the ordered pair where the graphs of the two functions intersect.

8 0
4 years ago
Arrange the following measurements in order from smallest to largest
natta225 [31]

Answer:

first we change 2000mm into litres and I think 1000 mm is equals to 1 L then you look at the first digit and in the first number we have for as the first digit the second number 0 the third number two so in this case 0.7 l is the smallest then 2000mm then 4.1 letters

6 0
4 years ago
Read 2 more answers
The sum of the first three terms in a GP is 38.Their product is 1728.Find the values of the three terms.
dusya [7]

Answer:

The value of the three terms is 8 and 18

Step-by-step explanation:

Let "a" be the first term and "r" be the common ratio.

Then from the condition, we have these two equations

   a + ar + ar^2  =   38,      (1)

   a*(ar*)*(ar^2) = 1728.      (2)

From equation (2),  a^3*r^3 = 1728,  or  (ar)^3 = 1728,   which implies

   ar = root%283%2C1728%29 = 12;          (3)    

hence,  

   r  = 12%2Fa.                   (4)

Now, in equation (1) replace the term  ar  by 12, based on (3).  You will get

   a + 12 + ar^2 =  38,   which implies

   a + ar^2 = 26.              (5)

Next, substitute  r = 12%2Fa  into equation (5), replacing "r" there.  You will get

   a + a%2A%28144%2Fa%5E2%29 = 26,   or

   a + 144%2Fa = 26.

Multiply by "a" both sides and simplify

   a^2 - 26a + 144 = 0,

   %28a-13%29%5E2 - 169 + 144 = 0

   %28a-13%29%5E2 = 25

   a - 13 = +/- sqrt%2825%29 = +/- 5.

Thus two solutions for "a" are  a = 13 + 5 = 18  or  a = 13 - 5 = 8.

If  a =  8, then from (4)  r = 12%2F8 = 3%2F2.

If  a = 18, then from (4)  r = 12%2F18 = 2%2F3.

   

In the first case, if a = 8,  then the three terms are  8, 8%2A%283%2F2%29 = 12  and  8%2A%283%2F2%29%5E2 = 18.

   In this case, the sum of terms is  8 + 12 + 18 = 38, so this solution does work.

In the second case, if a = 18,  then the three terms are  18, 18%2A%282%2F3%29 = 12  and  18%2A%282%2F3%29%5E2 = 8.

   In this case, the sum of terms is  18 + 12 + 8 = 38, so this solution does work, too.

ANSWER.  The problem has two solution:  

        a)  first term is 18;  the common difference is 2%2F3  and the progression is  18, 12, 8.

        b)  first term is  8;  the common difference is 3%2F2  and the progression is   8, 12, 18.

4 0
3 years ago
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