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Serjik [45]
4 years ago
8

Rob is setting up a model train track that is 3 3/8 feet long no telephone pole is needed at the start of the track. However alo

ng the track he places a telephone pole every 3/8. Foot a part. How many telephone poles dose he need
Mathematics
1 answer:
SOVA2 [1]4 years ago
7 0
First we need to convert 3 3/8 into 1/8ths:

3 \frac{3}{8} = \frac{27}{8}

Now, we need to see how many times 3/8 goes into 27/8:

\frac{27}{8} \div \frac{3}{8} = 27 \div 3 = 9

So we know he needs 9 telephone poles
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7 0
3 years ago
Given klmn is a trapezoid, kl = mn, m<1 = m<2, lm/kn = 8/9, pklmn = 132. Find: the length of the legs
Ilia_Sergeevich [38]

Answer:

The length of legs lm, mn, and lk is 32 while that of kn is 36.

Step-by-step explanation:

The diagram is attached in the answer.

As both the angles are equal thus the two forms isosceles triangles. This is true because the converse of base angle theorem is applicable here. The theorem clearly states that when a trapezoid is divided by the diagonal, it forms two set of angles where m<1=m<2 and m<lmk=m<nmk

This leads the two set of legs such as

\dfrac{lm}{kn}=\dfrac{8}{9}

Or this could be written as

lm=8x\\kn=9x

Now the remaining two sides are given as

lk=lm as this form an isosceles triangle so

lk=8x

Similarly

mn=lm\\

Or

mn=8x

Now the perimeter is given as

\text{perimeter}=lm+mn+kn+lk\\

Here perimeter is given as 132 so this gives:

\text{perimeter}=lm+mn+kn+lk\\132=8x+8x+8x+9x\\132=33x\\x=\dfrac{132}{33}\\x=4

So the four legs are of length as given below:

lm=8x=8\times 4=32\\mn=8x=8\times 4=32\\lk=8x=8\times 4=32\\kn=9x=9\times4=36

So the length of legs lm, mn, and lk is 32 while that of kn is 36.

6 0
3 years ago
2x-3(2x-3)+2=45 pls solve fully
ANEK [815]

Answer:x=-17/2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is -4+(-8+j)= simplified
fgiga [73]

Answer:

Step-by-step explanation:

−4−8+j

=−4+−8+j

Combine Like Terms:

=−4+−8+j

=(j)+(−4+−8)

=j+−12

Answer:

=j−12

6 0
3 years ago
Prove identity: tanx-1/tanx+1= 1-cotx/1+cotx
Marina CMI [18]
<span>to answer the question above, take the LHS. 
[(tan x - 1) / (tan x + 1)] = 

Remember that tan x = 1 / cot x. 
{[(1 / cot x) - 1] / [(1 / cot x) + 1]} = 

The LCD is cot x. Multiply as needed to get the common denominator for all terms. 
{[(1 / cot x) - 1(cot x / cot x)] / [(1 / cot x) + 1(cot x / cot x)]} = 
{[(1 / cot x) - (cot x / cot x)] / [(1 / cot x) + (cot x / cot x)]} = 

Then Simplify. 
[(1 - cot x) / cot x] / [(1 + cot x) / cot x] = 


Remember that (a / b) / (c / d) = (a / b) * (d / c). 
[(1 - cot x) / cot x] * [cot x / (1 + cot x)] = 
[(1 - cot x) / (1 + cot x )] = 
RHS</span>
The answer is
 <span>[(tan x - 1) / (tan x + 1)] = [(1 - cot x) / (1 + cot x )] </span>
5 0
3 years ago
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