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MAVERICK [17]
3 years ago
6

how do you use equations to solve problems about area of rectangles parallelograms trapezoids and triangles

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0
Area of parellelogram and rectangle=bh

trapezoid A=(b1+b2)h÷2

triangle A=bh÷2
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A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
What is the formula for the area of a rectangle?
PtichkaEL [24]

Answer:

The area of a rectangle is length*width

Step-by-step explanation:

The answer is A

This is simple

6 0
3 years ago
Read 2 more answers
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
When two computers are working together, they can finish updating software in 9 minutes. How long would they take individually t
tensa zangetsu [6.8K]
First computer takes x min. For 1 min it does 1/x part of work.

Second computer takes (x+24) min. For one min it does 1/(x+24) part of work.

Both computers for one min do   (1/x+1/(x+24)) part of work.

At the same time, both computers for one min do 1/9 part of work.

\frac{1}{x} + \frac{1}{x+24} = \frac{1}{9} &#10;\\ \\  \frac{x+24+x}{x(x+24)} =  \frac{1}{9} &#10;\\ \\9(2x+24)=x^{2} +24x&#10;\\ \\ 18x+216=x^{2} +24x&#10;\\ \\ x^{2}+6x-216=0&#10;\\ \\ D=b^{2}-4ac=36+4*216 = 900&#10;\\ \\ x= \frac{-b+/- \sqrt{D} }{2a}  =  \frac{-6+/-30}{2} &#10;\\ \\ x_{1}=-18, x_{2}=12&#10;&#10;We can use only positive number here. So, &#10;&#10;for the first computer x=12 min,&#10;&#10; for second computer x+24=12+24= 36 min&#10;&#10;Answer 12 min and 36 min.


7 0
3 years ago
Find x please<br><br><br> 10.3<br><br><br> 9.6<br><br><br> 84<br><br><br> 9
valentinak56 [21]

The 2 small black lines through the sides of the triangle indicate that the 2 sides are the same length.

Because the 2 sides are the same the 2 bottom angles are also the same.


This means that 9x +3 = 84

Now we can solve for x:

9x +3 = 84

Subtract 3 from each side:

9x = 91

Divide both sides by 9:

x = 81 / 9

x = 9

4 0
3 years ago
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