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MariettaO [177]
3 years ago
15

In Andrew’s Furniture Shop, he builds bookshelves and tables. Each type of furniture takes him about the same time to make. He f

igures he has time to make at most 18 pieces of furniture by this Saturday. The materials for each bookshelf cost him $20.00 and the materials for each table cost him $45.00. He has $600.00 to spend on materials. Andrew makes a profit of $60.00 on each bookshelf and a profit of $100.00 for each table. How many of each piece of furniture should Andrew make to maximize profit?
Mathematics
1 answer:
olasank [31]3 years ago
5 0
Given:
Cost to build a bookshelf = $20
Cost to build a table = $45
Amount available to spend = $600

Let x =  number of bookshelves built.
Let y =  number of tables built.

The total number of bookshelves and tables =  18.
Therefore
x + y = 18.
 That is,
 y = 18 - x                    (1)

The total amount available to build x bookshelves and y tables = $600. Therefore
20x + 45y = 600
That is (dividing through by 5),
4x + 9y = 120            (2)

Substitute (1) into (2).
4x + 9(18 - x) = 120
4x + 162 - 9x = 120
-5x = -42
  x = 8.4
From (1),obtain
 y = 18 - 8.4 = 9.6

Because we cannot have fractional bookshelves and tables, we shall test values of x=8, 9 and y=9,10 for profit

Note: The profit is $60 per bookshelf and $100 per table.
If x = 8, then y = 18-8 = 10.
The profit = 8*60 + 10*100 =  $1480

If x = 9, then y = 18-9 = 9.
The profit = 9*60 + 9*100 = $1440

The choice of 8 bookshelves and 10 tables is more profitable.

Answer: 8 bookshelves and 10 tables.
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