Answer:
7 reservoirs
Step-by-step explanation:
1 yards = 3 feet => 3.5 yards = 10.5 feet
To determine how many numbers of reservoirs to reserve 90000, we first need to determine the capacity of each reservoirs (how much liquid one reservoir can contain) - which is equal to the volume.
The formula to calculate the volume of a circular cylinder is:
- <em>Volume of cylinder = Area of base x Height </em>
<em />
The base of this cylinder is a circle with radius equal to 4 feet. (
)
=> The are of the base is = 
= 3.14 x 4^2 = 50.24 feet square
=> The volume of cylinder = Area of base x Height
=> The volume of one cylinder = 50.24 x 10.5 = 527.52 Cubic foot
We have: 1 cubic foot = 28.317 liters
=> 1 liter = 1/28.317 cubic foot
=> 90000 liters equal to: 90000/28.317 = 3,178.303 cubic foot
The number of reservoirs needed to contain 90000 liters of liquid is:
3,178.303/527.52 = 6.025
=> So that it needs 7 reservoirs to store all 90000 liters of liquid.
Answer:
Step-by-step explanation:
We are looking for P(58 < x < 64). We need to find the percentage to the left of the z-scores for each of these numbers. To find the z scores, use the formula:
which gives us a z-score of -1. The percentage of numbers to the left of a z-score of -1 is .1586553
Now for the other z-score:
which gives us a z-score of .5. The percentage of numbers to the left of a z-score of .5 is .69146246
The lower percentage subtracted from the higher gives the area in question:
.69146246 - .1586553 = .53280716, or as a percentage, 53.3%, choice A.
Use the least common denominator(LCD) to solve this equation:
1 + (-2/3) - (9/2)
so, what is the LCM of 3 and 2 : 6
so, the LCD = 6
1 + (-2 x 2/6) - (9 x 3/6)
the 1 = 6/6
Put it back into the equation:
6/6 + (-4/6) - (27/6)
Then, take it out of the parenthesis:
6/6 - 4/6 - 27/6
Simplify:
= - 25/6
which is the answer.
Hope that helped !! Have a great day now
The spread is the minimum value to the maximum value. The range is the maximum minus the minimum value hope that helps
First question:. A and D. Second question: B and C .
