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4 years ago

What causes the wind to blow

2 answers:

8 0

<span>Air at the equator is warmed by the direct rays of the sun while air at the poles is cooled because the suns rays are not so direct. As air warms, it expands and becomes less dense therefore rises, similarly but vice versa for cool air.

Hope this helped </span>

dexar [7]4 years ago

5 0

The unequal heating on the earth causes wind to blow

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Each statement below is a definition or an example of force, work, potential energy, or kinetic energy. Drag each into the box t

marshall27 [118]

Answer:

yes

Explanation:

6 0

3 years ago

What is the final temperature when 50 g of water at 20°c is mixed with 75 g of water at 60°c

tatyana61 [14]

44C i think. Do you have options for the answer?

4 0

4 years ago

In a collision an object experiences impulses , this impulse can be determined by

astraxan [27]

In a collision an object experiences impulses, this impulse can be determined by the product of net force exerted upon it in the specific course of time.

<u>Explanation:</u>

An object experiences impulse due to the force exerted upon it in a particular time period.

i.e.

$\text {Impulse }=F \times \Delta t$

Where,

F - Force acted upon the object

$\Delta t$ - time interval for which the force act

According to the definition of Impulse, it is the integral of force (F) that acts upon any object over a time interval ∆t. It produces an equivalent change in the momentum and that too in the same direction as of the applied force (F).

Therefore, in order to find the impulse on an object, we have to find the force acted on it in a specific time interval.

8 0

3 years ago

At one instant a bicyclist is 21.0 m due east of a park's flagpole, going due south with a speed of 13.0 m/s. Then 21.0 s later,

andre [41]

Answer:

Part a)

$d = 21\sqrt2 = 29.7 m$

Part b)

Direction is 45 degree North of West

Part c)

$v_{avg} = 1.41 m/s$

Part d)

direction of velocity will be 45 Degree North of West

Part e)

$a = 0.875 m/s^2$

Part f)

$\theta = 45 degree$ North of East

Explanation:

Initial position of the cyclist is given as

$r_1 = 21.0 m$ due East

final position of the cyclist after t = 21.0 s

$r_2 = 21.0 m$ due North

Part a)

for displacement we can find the change in the position of the cyclist

so we have

$d = r_2 - r_1$

$d = 21\hat j - 21\hat i$

so magnitude of the displacement is given as

$d = 21\sqrt2 = 29.7 m$

Part b)

direction of the displacement is given as

$\theta = tan^{-1}\frac{y}{x}$

$\theta = tan^{-1}\frac{21}{-21}$

so it is 45 degree North of West

Part c)

For average velocity we know that it is defined as the ratio of displacement and time

so here the magnitude of average velocity is defined as

$v_{avg} = \frac{\Delta x}{t}$

$v_{avg} = \frac{29.7}{21}$

$v_{avg} = 1.41 m/s$

Part d)

As we know that average velocity direction is always same as that of average displacement direction

so here direction of displacement will be 45 Degree North of West

Part e)

Here we also know that initial velocity of the cyclist is 13 m/s due South while after t = 21 s its velocity is 13 m/s due East

So we have

change in velocity of the cyclist is given as

$\Delta v = v_f - v_i$

$\Delta v = 13\hat i - (-13\hat j)$

now average acceleration is given as

$a = \frac{\Delta v}{\Delta t}$

$a = \frac{13\hat i + 13\hat j}{21}$

so the magnitude of acceleration is given as

$a = \frac{13\sqrt2}{21} = 0.875 m/s^2$

Part f)

direction of acceleration is given as

$\theta = tan^{-1}\frac{y}{x}$

$\theta = tan^{-1}\frac{13}{13}$

$\theta = 45 degree$ North of East

4 0

3 years ago

PLZ HELP WILL GIVE BRAINLIEST

xxTIMURxx [149]

Answer:

12.7m/s

Explanation:

Given parameters:

Mass of the diver = 77kg

Height = 8.18m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use one of the motion equations.

v² = u² + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

v² = 0² + (2 x 9.8 x 8.18)

v² = 160.3

v = 12.7m/s

7 0

3 years ago