Question

Ohm’s Lawpls answer this photos​

Answer 1

Answer:

Trial 1: 2 Volts, 0 %

Trial 2: 2.8 Volts, 0%

Trial 3: 4 Volts, 0 %

Explanation:

Th experimental values are given in the table, while the theoretical value can be found by using Ohm/s Law:

V = IR

TRIAL 1:

V = IR

V = (0.1 A)(20 Ω)

V = 2 volts

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(2 - 2)/2| x 100%

% Difference = 0 %

TRIAL 2:

V = IR

V = (0.14 A)(20 Ω)

V = 2.8 volts

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(2.8 - 2.8)/2.8| x 100%

% Difference = 0 %

TRIAL 3:

V = IR

V = (0.2 A)(20 Ω)

V = 4 volts

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(4 - 4)/4| x 100%

% Difference = 0 %