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3 years ago

Ohm’s Lawpls answer this photos

Physics

1 answer:

Rudiy273 years ago

7 0

Answer:

Trial 1: 2 Volts, 0 %

Trial 2: 2.8 Volts, 0%

Trial 3: 4 Volts, 0 %

Explanation:

Th experimental values are given in the table, while the theoretical value can be found by using Ohm/s Law:

V = IR

<u>TRIAL 1</u>:

V = IR

V = (0.1 A)(20 Ω)

<u>V = 2 volts</u>

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(2 - 2)/2| x 100%

<u>% Difference = 0 %</u>

<u>TRIAL 2</u>:

V = IR

V = (0.14 A)(20 Ω)

<u>V = 2.8 volts</u>

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(2.8 - 2.8)/2.8| x 100%

<u>% Difference = 0 %</u>

<u></u>

<u>TRIAL 3</u>:

V = IR

V = (0.2 A)(20 Ω)

<u>V = 4 volts</u>

% Difference = $|\frac{Theoretical Value - Exprimental Value}{Theoretical Value}|$ x 100%

% Difference = |(4 - 4)/4| x 100%

<u>% Difference = 0 %</u>

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I need to know the right answer to that question

ad-work [718]

The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)

Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation

v = vo + at

When you plug in the values you get

v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.

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3 years ago

1. What is the momentum of a golf ball with a mass of 62 g moving at 73 m/s?

Anit [1.1K]

Answer:

<h3>The answer is 4.53 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 62 g = 0.062 kg

velocity = 73 m/s

We have

momentum = 0.062 × 73 = 4.526

We have the final answer as

Hope this helps you

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3 years ago

In a wire, when elongation is 4 cm energy stored is E. if it is stretched by 4 cm, then what amount of elastic potential energy

myrzilka [38]

<h2>Answer:</h2>

<h2>Explanation:</h2>

The elastic potential energy of an elastic material (e.g a spring, a wire), is the energy stored when the material is stretched or compressed. It is given by

U = $\frac{1}{2}kx^2$ --------------------(i)

Where;

U = potential energy stored

k = spring constant of the material

x = elongation (extension or compression of the material).

<em>From the first statement;</em>

<em>when elongation (x) is 4cm, energy stored (U) is E</em>

<em>Substitute these values into equation (i) as follows;</em>

E = $\frac{1}{2}k(4)^2$

E = 8k

<em>Make k subject of the formula</em>

k = $\frac{E}{8}$ [measured in J/cm]

<em>From the second statement;</em>

<em>It is stretched by 4cm.</em>

This means that total elongation will be 4cm + 4cm = 8cm.

The potential energy stored will be found by substituting the value of x = 8cm and k = $\frac{E}{8}$ into equation (i) as follows;

U = $\frac{1}{2}\frac{E}{8} (8)^2$

U = $\frac{1}{2}{8E}$

U = ${4E}$

Therefore, the potential energy stored will now be 4 times the original one.

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3 years ago

Please help me with these questions

Marta_Voda [28]

Radio waves - radio waves have the longest wavelengths of all the electromagnetic waves. they range from around a foot long to several miles long. Radio waves are often used to transmit data and have been used for all sorts of applications including radio, satellites, radar, and computer networks. hope it helps

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3 years ago

3. Two cars, both with a mass of 500 kg, are traveling down a road. The first car has a velocity of 65 m/s east and the second c

fenix001 [56]

Answers:

a) Momentum for Car 1: $p_{1}=32500kg.m/s$ East

Momentum for Car 2: $p_{2}=42500kg.m/s$ West

b) Car 2 has the greater momentum

Explanation:

a) The linear momentum $p$ is given by the following equation:

$p=m.v$ (1)

Where $m$ is the mass of the object and $v$ its velocity.

In this case both cars have a mass of $500kg$ but different velocities ( $v_{1}=65m/s$ east for car 1 and $v_{2}=85m/s$ west for car 2).

For Car 1:

$p_{1}=m.v_{1}$ (2)

$p_{1}=(500kg)(65m/s)$ (3)

$p_{1}=32500kg.m/s$ (4)

For Car 2:

$p_{2}=m.v_{2}$ (5)

$p_{2}=(500kg)(85m/s)$ (6)

$p_{2}=42500kg.m/s$ (7)

b) Having the result of the lineal momentum for both cars, we know Car 2 has the larger momentum, this can be known because Car 2 has a greater velocity.

So, if momentum is directly proportional to the mass and the velocity of the object, both objects have the same mass but different velocities; the object with greater mass will have the greater momentum.

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3 years ago

Ohm’s Lawpls answer this photos​

Ohm’s Lawpls answer this photos