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weqwewe [10]
3 years ago
13

Alberta is going to have dinner at her grandmother's house, but she is running a bit behind schedule. As she gets onto the highw

ay, she knows that she must exit the highway within 55
min

min

if she is not going to arrive late. Her exit is 43

mi

miHow much time would it take at the posted 60 mph speed?

away.
Physics
1 answer:
viktelen [127]3 years ago
5 0

Complete Question

Alberta is going to have dinner at her grandmother's house, but she is running a bit behind schedule. As she gets onto the highway, she knows that she must exit the highway within 55 min if she is not going to arrive late. Her exit is 43 mi away. How much time would it take at the posted 60 mph speed?

Answer:

The time it would take at the given speed is  x = 43.00 \ minutes

Explanation:

From the question we are told that

      The time taken to exist the highway is  t = 55 min

      The distance to the exist is  d =  43\  mi

       Alberta speed is v =  60 mph

The time it would take travelling at the given speed is mathematically represented as

        t_z = \frac{d}{v}

  substituting values

        t_z = \frac{43}{60}

        t_z = 0.71667\ hrs

Converting to minutes

         1  hour =  60 minutes

So      0.71667 hours = x minutes

   Therefore

               x = 0.71667 * 60

                x = 43.00 \ minutes

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B. Projectile on cliff (range)
dimulka [17.4K]

Answer:

x = 41.28 m

Explanation:

This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.

Let's start by using trigonometry to find the initial velocity

         cos 25 = v₀ₓ / v₀

         sin 25 = Iv_{oy} / v₀

         v₀ₓ = v₀ cos 25

         v_{oy} = v₀ sin 25

         v₀ₓ = 22 cos 25 = 19.94 m / s

         v_{oy} = 22 sin 25 = 0.0192 m / s

let's use movement on the vertical axis

         y = y₀ + v_{oy} t - ½ g t²

     

when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m

         0 = 21 + 0.0192 t - ½ 9.81 t²

         4.905 t² - 0.0192 t - 21 = 0

         t² - 0.003914 t - 4.2813 =0

we solve the quadratic equation

        t = \frac{ 0.003914\  \pm \sqrt{0.003914^2 + 4 \ 4.2813 }   }{2}

        t = \frac{0.003914 \ \pm 4.13828}{2}

        t₁ = 2.07 s

        t₂ = -2.067 s

since time must be a positive scalar quantity, the correct result is

        t = 2.07 s

now we can look up the distance traveled

         x = v₀ₓ t

         x = 19.94  2.07

         x = 41.28 m

5 0
3 years ago
You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.
tatyana61 [14]

Given the following choices;

A) less than your true weight, mg.

B) equal to your true weight, mg.

C) more than your true weight, mg.

D) could be more or less than your true weight, mg, depending on the value of the speed.

The answer is; C

This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.  

8 0
2 years ago
Read 2 more answers
When did the ball fly farther—when it hit the moving bat or the bat that did not move?
8_murik_8 [283]

Answer:

when it hit the moving bat

Explanation:

force equals mass times acceleration which means the moving bat will add more force to the ball.

6 0
3 years ago
A 1-megabit computer memory chip contains many 27 fF capacitors. Each capacitor has a plate area of 3.09 × 10−11 m 2 . Determine
valentina_108 [34]

Answer:

Plate separation of each capacitor is 101.132 °A

Explanation:

The formula to calculate the capacitance in empty space as a function of distance (square parallel plates) is:

C=\epsilon_{0}\frac{Area}{distance}

clearing for distance:

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8 0
3 years ago
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finlep [7]
In this question a lot of information's are provided. Among the information's provided one information and that is the time of 4 seconds is not required for calculating the answer. Only the other information's are required.
Mass of the block that is sliding = 5.00 kg
Distance for which the block slides = 10 meters/second
Then we already know that
Momentum = Mass * Distance travelled
                   = (5 * 10) Kg m/s
                   = 50 kg m/s
So the magnitude of the blocks momentum is 50 kg m/s. The correct option among all the given options is option "b".
5 0
3 years ago
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