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fiasKO [112]
4 years ago
7

(03.02 MC)

Chemistry
1 answer:
dusya [7]4 years ago
5 0

Answer: B

Explanation:

K is +1 & S is -2 ==> K2S

Potassium sulfide is the inorganic compound with the formula K₂S. The colourless solid is rarely encountered, because it reacts readily with water, a reaction that affords potassium hydrosulfide and potassium hydroxide.

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Hello I need help very bad!!!
Oksanka [162]

D. Cell membrane: surrounds a cell and allows substances to pass in and out

6 0
3 years ago
∆G° for the reaction of nitrogen with hydrogen to produce ammonia (see balanced chemical equation below) has a value of -33.3 kJ
Juliette [100K]

Answer:

-0.85KJ

Explanation:

Given N2(g) + H2(g) <--->2NH3(g)

Kp =[ P(NH3)]²/[P(H2)]³[P(N2)]

Where P is the pressure of the gas

P(H2)b= P(N2) = 125atm

P(NH3) = 200atm

Kp = 2²/(125)³(125)

Kp = 2.048 ×10^-6

∆G = -RTlnKp

R =0.008314 J/Kmol

T = 25 +273/= 298k

= 8.314 ×10^-3 × 298 × ln(2.048 ×10^-6)

= -0.008314 × 298 × (-13.099)

= 32.45KJ

∆G = ∆G° + RTlnKp

∆G = -33.3 + 32.45

∆G = -0.85KJ or -850J

3 0
4 years ago
The specific heat of gasoline is 2.22 J/g•°C. How much heat would it take to raise 35.0 G of gasoline to 3.00°C?
Olenka [21]
<span>To find the amount of heat energy required to raise a substance by a certain number of degrees, we simply multiply: (specific heat * change in temperature * mass) Heat = 2.22 * 35 * 3 = 233.1 joules Therefore, we would need 233.1 joules of heat to raise the temperature by 3 degrees Celsius.</span>
3 0
4 years ago
I am confused, can somebody help me?
Ronch [10]

Answer:

electrons 79

neutrons 188

6 0
3 years ago
Read 2 more answers
According to the following reaction, how many grams of water are produced in the complete reaction of 29.7 grams of ammonia? 4 N
Gnesinka [82]

<u>Answer:</u> The mass of water produced in the reaction is 47.25 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ammonia = 29.7 g

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{29.7g}{17g/mol}=1.75mol

The given chemical reaction follows:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

By stoichiometry of the reaction:

4 moles of ammonia produces 6 moles of water.

So, 1.75 moles of ammonia will produce = \frac{6}{4}\times 1.75=2.625mol of water.

Now, calculating the mass of water by using equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 2.625 moles

Putting values in equation 1, we get:

2.625mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=47.25g

Hence, the mass of water produced in the reaction is 47.25 grams.

3 0
3 years ago
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