Question

A sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 atm and a temperature of 20.3°C. It was placed in an ice chest whose internal temperature is -2.0°C. What will be the new pressure of the gas sample once the gas temperature in the jar equilibrates to that of the ice chest?

Answer 1

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Answer 2

Answer: The new pressure of the gas sample once the gas temperature in the jar 0.9424 atm.

Explanation:

Volume of the gas = 250 mL

Pressure of the gas at $T_1=P_1$

Pressure of the gas at $T_2=P_2$

At the constant volume pressure of the gas is directly proportional to the temperature of the gas in Kelvins that is Gay-Lussac's Law

$P_1=1.02 atm$ , $T_1=20.3^oC=293.3 K$

$P_2=?$ , $T_2=-2^oC=271 K$

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$\frac{P_1}{T_1}\times T_2=P_2=\frac{1.02 atm}{293.3 K}\times 271 K=0.9424 atm$

The new pressure of the gas sample once the gas temperature in the jar 0.9424 atm.