Answer:
physical
Explanation:
if it is asking to determine what it is a sign of or how to identify that characteristic it would be a physical.
Convert moles to mass.
mass C = 0.2 mol * 12 g / mol = 2.4 g
mass H = 0.4 mol * 1 g / mol = 0.4 g
So mass left for O = 6 g – (2.4 g + 0.4 g) = 3.2 g
Calculating for moles O given mass:
moles O = 3.2 g / (16 g / mol) = 0.2 moles
Answer:
<span>0.2 moles O</span>
mass percent concentration = 15.7 %
molar concentration of glucose solution 1.03 M
Explanation:
To calculate the mass percent concentration of the solution we use the following formula:
concentration = (solute mass / solution mass) × 100
solute mass = 60.5 g
solution mass = solute mass + water mass
solution mass = 60.5 + 325 = 385.5 g (I used the assumption that the solution have a density of 1 g/mL)
concentration = (60.5 / 385.5) × 100 = 15.7 %
Now to calculate the molar concentration (molarity) of the solution we use the following formula:
molar concentration = number of moles / volume (L)
number of moles = mass / molecular weight
number of moles of glucose = 60.5 / 180 = 0.336 moles
molar concentration of glucose solution = 0.336 / 0.325 = 1.03 M
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molarity
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The other dude is rude wrong
The correct answer is Dmitri Mendeleev
Answer:
Ferrous Oxide, FeO is an inorganic compound.
