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Oksanka [162]
3 years ago
11

What is the equivalent resistance in this circuit? What is the current in this circuit?

Physics
2 answers:
suter [353]3 years ago
5 0

Answer:

15 Ohms

3 Amps

Explanation:

kramer3 years ago
3 0

All these resistors are in series so we can take the sum of them by:

Rtotal = R1 + R2 + R3......

So...

Rtotal = 2 + 3 + 4 + 6

Rtotal = 15

So now the total resistance in the circuit is 15 ohms and the potential difference applied to the circuit is 45 volts

Now we can use:

V = IR

Isolate for I

V/R = I

45/15 = I

I = 3 amps (A)

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Answer:

U = (ε0AV^2) / 2d

Explanation:

Where C= capacitance of the capacitor

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A= cross sectional area of plates

d= distance between the plates

V= potential difference

First, the capacitance of a capacitor is obtained by:

C = ε0A/d.

Starting at the formula , U= (CV^2)/2. Formula for energy stored in a capacitor

Substitute in for C:

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3 years ago
What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm
nadezda [96]
<h3><u>Given</u> :</h3>

Current flow light bulb = 2.5\sf{A}

Resistance of light bulb = 3.6Ω

<h3><u>To Find </u>:</h3>

We have to find voltage of battery.

<h3><u>Solution</u> :</h3>

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

➝ <u>V = I × R</u>

Where, R is the resistance of conductor.

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A water balloon is thrown horizontally from a tower that is 45 m high. It strikes the shoes of an unsuspecting passerby who is 4
LekaFEV [45]

Answer:

14.85 m/s

Explanation:

From the question given above, the following data were obtained:

Height (h) of tower = 45 m

Horizontal distance (s) moved by the balloon = 45 m

Horizontal velocity (u) =?

Next, we shall determine the time taken for the balloon to hit the shoe of the passerby. This is illustrated below:

Height (h) of tower = 45 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

45 = ½ × 9.8 × t²

45 = 4.8 × t²

Divide both side by 4.9

t² = 45/4.9

Take the square root of both side

t = √(45/4.9)

t = 3.03 s

Finally, we shall determine the magnitude of the horizontal velocity of the balloon as shown below:

Horizontal distance (s) moved by the balloon = 45 m

Time (t) = 3.03 s

Horizontal velocity (u) =?

s = ut

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Divide both side by 3.03

u = 45/3.03

u = 14.85 m/s

Thus, the magnitude of the horizontal velocity of the balloon was 14.85 m/s

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