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solong [7]
4 years ago
12

How should the distance, D, between two point charges, q1 and q2, be changed to double their electric potential energy

Physics
1 answer:
Licemer1 [7]4 years ago
6 0

The electrostatic potential energy, U, of one point charge q at position d in the presence of an electric field E is defined as the negative of the work W done by the electrostatic force to bring it from the reference position d to that position

u \:  =  \:  \frac{kq1q2}{d}

Thus, to double the electric potential energy U we need to reduce the distance of separation by half (1/2) because they are inversely proportion

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Correct your friend that says, "The dragster rounded the curve at a constant velocity of 100 km/h." In other words, what is wron
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Answer:

Correct statement will be dragster rounded the curve with constant speed

Explanation:

It is given that his fried says that The dragster rounded the curve with a constant velocity of 100 km/hour

It is a wrong statement because in circular motion velocity will never constant as the direction of speed is always changing

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8 0
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Water having a density of 1000 kg/m^3 is flowing with a velocity of 3 m/s through a round pipe. There is a restriction within th
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Answer:

12 m/s

Explanation:

Using the continuity equation, which is an extension of the conservation of mass law

ρ₁A₁v₁ = ρ₂A₂v₂

where 1 and 2 indicate the conditions at two different points of flow, in this case, point 1 is any normal position in the pip and point 2 is the conditions at the restriction.

ρ = density of the fluid flowing; note that the density of the fluid flowing (water) is constant all through the fluid's flow

A₁ = Cross sectional Area of the pipe at point 1 = (πD₁²/4)

A₂ = Cross sectional Area of the pipe at the restriction = (πD₂²/4)

v₁ = velocity of the fluid flowing at point 1 = 3 m/s

v₂ = velocity of the fluid flowing at The restriction = ?

ρ₁A₁v₁ = ρ₂A₂v₂

Becomes

A₁v₁ = A₂v₂ (since ρ₁ = ρ₂)

(πD₁²/4) × 3 = (πD₂²/4) × v₂

3D₁² = D₂² × v₂

But

D₂ = (D₁/2)

And D₂² = (D₁²/4)

3D₁² = D₂² × v₂

3D₁² = (D₁²/4) × v₂

(D₁²/4) × v₂ = 3D₁²

v₂ = 4×3 = 12 m/s

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